A) 83.33 ml | B) 90.90 ml |

C) 99.09 ml | D) can't be determined |

Explanation:

Profit (%) = 9.09 % =

Since the ratio of water and milk is 1 : 11,

Therefore the ratio of water is to mixture = 1:12

Thus the quantity of water in mixture of 1 liter = = 83.33 ml

A) 11 lit | B) 22 lit |

C) 33 lit | D) 44 lit |

Explanation:

Let the capacity of the pot be 'P' litres.

Quantity of milk in the mixture before adding milk = 4/9 (P - 4)

After adding milk, quantity of milk in the mixture = 6/11 P.

6P/11 - 4 = 4/9(P - 4)

10P = 396 - 176 => P = 22.

The capacity of the pot is 22 liters.

A) 5:3 | B) 1:4 |

C) 4:1 | D) 9:1 |

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

The ratio of milk and water in the new mixture = 16:4 = 4:1

If the process is repeated one more time and 10 liters of the mixture are removed,

then amount of milk removed = 4/5 x 10 = 8 liters.

Amount of water removed = 2 liters.

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

Now 10 lts milk is added => total milk = 18 lts

The required ratio of milk and water in the final mixture obtained

= (8 + 10):2 = 18:2 = 9:1.

A) 2 lit | B) 4 lit |

C) 1 lit | D) 3 lit |

Explanation:

Quantity of fruit juice in the mixture = 90/100 (70) = 63 litres.

After adding water, juice would form 87 1/2% of the mixture.

Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72

Hence 72 - 70 = 2 litres of water must be added.

A) 5 lit | B) 10 lit |

C) 15 lit | D) 20 lit |

Explanation:

Number of liters of water in 150 liters of the mixture = 20% of 150 = 20/100 x 150 = 30 liters.

P liters of water added to the mixture to make water 25% of the new mixture.

Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).

(30 + P) = 25/100 x (150 + P)

120 + 4P = 150 + P => P = 10 liters.

A) 360 ml | B) 320 ml |

C) 310 ml | D) 330 ml |

Explanation:

Here total parts of milk and water in the solution is 6+2 = 8 parts

1part = 640/8 = 80

old mixture contains 6parts of milk and 2 parts of water(6:2).

To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.

i.e, 4 x 80 = 320 ml.