35
Q:

# A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?

 A) 10 liters B) 20 liters C) 30 liters D) 40 liters

Explanation:

Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters

Let us Assume that another 'P' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P)

Thus, (30 + P) = 25% of (150 + P)

Solving, we get P = 10 liters

Q:

An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ?

 A) 113/108 B) 105/103 C) 108/115 D) 103/113

Explanation:

As given equal amounts of alloys are melted, let it be 1 kg.

Required ratio of gold and silver =

Hence, ratio of gold and silver in the resulting alloy = 105/103.

4 401
Q:

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

 A) 58 l B) 65 l C) 50 l D) 62 l

Explanation:

Let the tin contain 5x litres of liquids

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

= 50 litres.

8 1201
Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

 A) 45 gm B) 50 gm C) 55 gm D) 60 gm

Explanation:

Initial quantity of copper = = 40 g

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

6 972
Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

 A) 1 : 10 B) 10 : 1 C) 9 : 11 D) 11 : 9

Explanation:

Customer ratio of Milk and Water is given by

Milk          ::        Water

6.4                         0

$\frac{64}{11}$

=> Milk : Water = 110 : 11 = 10 : 1

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

13 980
Q:

In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture?

 A) 1:1 B) 2:1 C) 3:1 D) 1:2

Explanation:

Quantity of alohol in the mixture = 40 x 5/8 = 25 lit

Quantity of water = 40 - 25 = 15 lit

According to question,

Required ratio =

9 1430
Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

 A) 85 B) 60 C) 55 D) 45

Explanation:

Let M litres milk be added

=>

=> 60 + M = 120

=> M = 60 lit.

8 655
Q:

A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal.

 A) 31.8% B) 31% C) 33.33% D) 29.85%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

50

50            25  = 2 : 1

Hence required answer =  1/3 or 33.33%

15 895
Q:

The concentration of glucose in three different mixtures (glucose and alcohol) is  respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture?

 A) 3:2 B) 4:3 C) 2:3 D) 3:4

Explanation:

Concentration of glucose are in the ratio = $\frac{1}{2}:\frac{3}{5}:\frac{4}{5}$

Quantity of glucose taken from A = 1 liter out of 2

Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit

Quantity of glucose taken from C = 0.8 lit

So, total quantity of glucose taken from A,B and C = 3.6 lit

So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit

Ratio of glucose to alcohol = 3.6/2.4 = 3:2