Alligation or Mixture Questions

FACTS  AND  FORMULAE  FOR  ALLIGATION  OR  MIXTURE  QUESTIONS

 

 

I. Alligation : It is the rule that enables us to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture of a desired price.

 

II. Mean Price : The cost price of a unit quantity of the mixture is called the mean price.

 

III. Rule of Alligation : Suppose Rs.x per unit be the price of first ingradient mixed with another ingradient (cheaper) of price Rs.y per unit to form a mixture whose mean price is Rs. z per unit, then 

Quantity of cheaper : Quantity of dearer

       = ( C.P of dearer - Mean Price ) : ( Mean Price - C. P of cheaper )

       = ( x- z ) : ( z - y )

 

 IV. Suppose a container contains x units of liquid from which y units are taken out and replaced by water. After  operations , the quantity of pure liquid = x1-yxn units.

 

Q:

A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 

A) 31.8% B) 31%
C) 33.33% D) 29.85%
 
Answer & Explanation Answer: C) 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

       50

50            25  = 2 : 1

 

Hence required answer =  1/3 or 33.33%

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27 6118
Q:

The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture? 

A) 3:2 B) 4:3
C) 2:3 D) 3:4
 
Answer & Explanation Answer: A) 3:2

Explanation:

Concentration of glucose are in the ratio = 12:35:45

Quantity of glucose taken from A = 1 liter out of 2

Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit

Quantity of glucose taken from C = 0.8 lit

So, total quantity of glucose taken from A,B and C = 3.6 lit

So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit

Ratio of glucose to alcohol = 3.6/2.4 = 3:2

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23 6086
Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm B) 50 gm
C) 55 gm D) 60 gm
 
Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper =80100 x 50 = 40 g 

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> 50 + p x 90100 = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

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19 6055
Q:

Two bottles contains mixture of milk and water. First bottle contains 64% milk and second bottle contains 26% water. In what ratio these two mixtures are mixed so that new mixture contains 68% milk?

A) 3 : 2 B) 2 : 1
C) 1 : 2 D) 2 : 3
 
Answer & Explanation Answer: A) 3 : 2

Explanation:

% of milk in first bottle = 64%

% of milk in second bottle = 100 - 26 = 74%

Now, ATQ

 

64%            74%
         

         68%

 

6                    4

 

Hence, by using allegation method,

 

Required ratio = 3 : 2

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11 6052
Q:

Ratio of water and milk in a container is 2 : 3. If 40 liter mixture removed from the container and same quantity of milk is added to it then the ratio of water to milk becomes 1 : 4. Find the initial quantity of mixture ?

 

A) 75 lit B) 80 lit
C) 85 lit D) 90 lit
 
Answer & Explanation Answer: B) 80 lit

Explanation:

From the given data,

let the initial quantity of the mixture = 5x

Then,

2x - 163x - 24 + 40 = 148x - 64 = 3x + 165x = 80x = 16 lit

 

Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

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38 5682
Q:

In a mixture of 240 lt. water is 20% and rest is Milk. What quantity of mixture should be taken out and replaced with water so that water becomes 40%?

A) 60 lit B) 55 lit
C) 45 lit D) 50 lit
 
Answer & Explanation Answer: A) 60 lit

Explanation:

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15 5668
Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

A) 85 B) 60
C) 55 D) 45
 
Answer & Explanation Answer: B) 60

Explanation:

Let M litres milk be added


=> 60 + M40 = 31


=> 60 + M = 120


=> M = 60 lit.

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15 4877
Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

A) 2:3 B) 4:3
C) 3:4 D) 3:2
 
Answer & Explanation Answer: D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

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17 4811