Decimal Fractions Questions

FACTS  AND  FORMULAE  FOR  DECIMAL  FRACTION  QUESTIONS

 

 

I. Decimal Fractions : Fractions in which denominators are powers of 10 are known as decimal fractions.Thus

1/10 = 1 tenth = .1;

1/100 = 1 hundredth = .01;

99/100 = 99 hundreths = .99;

7/1000 = 7 thousandths = .007 etc

 

II. Conversion of a Decimal Into Vulgar Fraction : Put 1 in the denominator under the decimal point and annex with it as many zeros as is the number of digits after the decimal point.

Now, remove the decimal point and reduce the fraction to its lowest terms. Thus

0.25 = 25/100 = 1/4;

2.008 = 2008/1000 = 251/125.

 

III. 

1. Annexing zeros to the extreme right of a decimal fraction does not change its value.

Thus, 0.8 = 0.80 = 0.800, etc.      

2. If numerator and denominator of a fraction contain the same number of decimal places, then we remove the decimal sign.Thus

1.84/2.99 = 184/299 = 8/13;     

0.365/0.584 = 365/584 = 5/8

 

IV. Operations on Decimal Fractions :

1. Addition and Subtraction of Decimal Fractions : The given numbers are so placed under each other that the decimal points lie in one column. The numbersso arranged can now be added or subtracted in the usual way.


2. Multiplication of a Decimal Fraction By a Power of 10 : Shift the decimal point to the right by as many places as is the power of 10. Thus

5.9632 x 100 = 596.32;

0.073 x 10000 = 0.0730 x 10000 = 730.


3.Multiplication of Decimal Fractions : Multiply the given numbers considering them without the decimal point. Now, in the product, the decimal point is marked off to obtain as many places of decimal as is the sum of the number of decimal places in the given numbers.

Suppose we have to find the product (.2 x .02 x .002).

Now, 2 x 2 x 2 = 8. Sum of decimal places = (1 + 2 + 3) = 6.  

Therefore, .2 x .02 x .002 = .000008.


4.Dividing a Decimal Fraction By a Counting Number : Divide the given number without considering the decimal point, by the given counting number.Now, in the quotient, put the decimal point to give as many places of decimal as there are in the dividend.

Suppose we have to find the quotient (0.0204 / 17).

Now, 204 / 17 = 12. Dividend contains 4 places of decimal.

So, 0.0204 / 17 = 0.0012.


5. Dividing a Decimal Fraction By a Decimal Fraction : Multiply both the dividend and the divisor by a suitable power of 10 to make divisor a whole number. Now, proceed as above.

Thus, 0.00066/0.11 = (0.00066 x 100)/(0.11 x 100) = (0.066/11) = 0.006


V. Comparison of Fractions : Suppose some fractions are to be arranged in ascending or descending order of magnitude. Then, convert each one of the given fractions in the decimal form, and arrange them accordingly.

Suppose, we have to arrange the fractions 3/5, 6/7 and 7/9 in descending order. now, 3/5=0.6,   6/7 = 0.857,  7/9 = 0.777.... since 0.857 > 0.777... > 0.6

 So 6/7 > 7/9 > 3/5

 

VI. Recurring Decimal : If in a decimal fraction, a figure or a set of figures is repeated continuously, then such a number is called a recurring decimal. In a recurring decimal, if a single figure is repeated, then it is expressed by putting a dot on it. If a set of figures is repeated, it is expressed by putting a bar on the set .

Thus 1/3 = 0.3333….= 0.3; 22 /7 = 3.142857142857..... = 3.142857¯

Pure Recurring Decimal: A decimal fraction in which all the figures after the decimal point are repeated, is called a pure recurring decimal.

Converting a Pure Recurring Decimal Into Vulgar Fraction : Write the repeated figures only once in the numerator and take as many nines in the denominator as is the number of repeating figures.

Thus , 0.5=59; 0.53¯ = 5399; 0.067¯=67999etc...

Mixed Recurring Decimal: A decimal fraction in which some figures do not repeat and some of them are repeated, is called a mixed recurring decimal. e.g., 0.17333 = 0.173¯

Converting a Mixed Recurring Decimal Into Vulgar Fraction : In the numerator, take the difference between the number formed by all the digits after decimal point (taking repeated digits only once) and that formed by the digits which are not repeated, In the denominator, take the number formed by as many nines as there are repeating digits followed by as many zeros as is the number of non-repeating digits.

Thus, 0.16 = (16-1) / 90 = 15/90 = 1/6;  

0.2273¯=2273-229900=22519900

 

VII. Some Basic Formulae : 

1.a+ba-b=a2-b2

2. a+b2=a2+b2+2ab

3. a-b2=a2+b2-2ab

4. a+b+c2=a2+b2+c2+2ab+bc+ca

5. a3+b3=a+ba2-ab+b2

6. a3-b3=a-ba2+ab+b2

7. a3+b3+c3-3abc=a+b+ca2+b2+c2-ab-bc-ac

8. When a+b+c=0, then a3+b3+c3=3abc

Q:

If 47. 2506 = 4*A + 7/B + 2*C + 5/D + 6*E, then the value of 5*A + 3*B + 6*C + D + 3*E is :

A) 55.6003 B) 53.603
C) 153.6003 D) 213.003
 
Answer & Explanation Answer: C) 153.6003

Explanation:

4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003.

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

60 16445
Q:

A person was asked to state his age in years. His reply was , "Take my age 3 years hence, multiply it by 3 and subtract 3 times my age 3 years ago and you will know how old I am." What was the age of the person ?

A) 18 B) 20
C) 24 D) 30
 
Answer & Explanation Answer: A) 18

Explanation:

Let the present age of person be   x years.

Then, 3(x + 3) - 3(x - 3 ) = x   <=> (3x + 9) - (3x - 9) = x  <=> x = 18..

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

16 14367
Q:

125 over 1000 in Simplest Form?

A) 2/9 B) 1/8
C) 3/8 D) 4/7
 
Answer & Explanation Answer: B) 1/8

Explanation:

125 over 1000 in Simplest Form means 1251000 in its simple fraction form.

 

Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.

 

HCF of 125, 1000 = 125

 

Then, divide both numerator and denominator by 125

i.e, 1251251000125 = 18

 

Hence, 18 is the simplest form of 125 over 1000.

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

36 13320
Q:

4.036 divided by 0.04 gives 

A) 1.009 B) 10.09
C) 100.9 D) None of these
 
Answer & Explanation Answer: C) 100.9

Explanation:

4.036/0.04 = 4036/40 = 100.9

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

16 12788
Q:

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases  by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity?

A) 2010 B) 2011
C) 2012 D) 2013
 
Answer & Explanation Answer: B) 2011

Explanation:

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

        (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

=>  0.25Z = 0.40 + 2.10  => Z= 2.50/0.25 = 10

Therefore, X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

9 11578
Q:

When 52416 divided by 312 , the quotient is 168. What will be the quotient when 52.416 is  divided by 0.0168 ?

A) 3120 B) 32.10
C) 321.0 D) 3.120
 
Answer & Explanation Answer: A) 3120

Explanation:

Given, 52416 / 312 = 168.

<=>  52416 / 168 = 312.

52.416 / 0.0168 = 524160 / 168 = 3120.

 

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

7 11003
Q:

The expression (11.98 * 11.98 + 11.98 * (x) + 0.02 * 0.02) will be a perfect square for x equal to :            

A) 0.01 B) 0.02
C) 0.03 D) 0.04
 
Answer & Explanation Answer: D) 0.04

Explanation:

Given = (11.98)^2 + (0.02)^2 + 11.98 * x. 

For the given expression to be a perfecr square, we must have

11.98 * x = 2 * 11.98 * 0.02 => x = 0.04

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions

13 9446
Q:

Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ?

A) 404 B) 415
C) 418 D) 420
 
Answer & Explanation Answer: C) 418

Explanation:

Let the total book be 1

Then, in the 1st week 613th of book is read

i.e remaining pages =  1-613=713


in 2nd week he read 59th of it

i.e 59×713=35117
Remaining pages after 2nd week = 713-35117=28117

But given remaining pages after 2nd week = 100

 

28x117=100

--> x = 418 

 The total pages in the book are 418

Report Error

View Answer Report Error Discuss

Filed Under: Decimal Fractions
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

16 9346