Problems on Ages Questions

Q:

"I am five times as old as you were, when I was as old as you are", said a man to his son. Find out their present ages, if the sum of their ages is 64 years ?

A) Father = 50; Son =14 B) Father = 40; Son =24
C) Father = 60; Son =4 D) Father = 48; Son =16
 
Answer & Explanation Answer: B) Father = 40; Son =24

Explanation:

Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.

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109 26419
Q:

Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev?

A) 12 B) 14
C) 22 D) 10
 
Answer & Explanation Answer: D) 10

Explanation:

Let Rajeev's present age be  x years.

Rajeev's age after 15 years = (x + 15) years.

Rajeev's age 5 years back = (x - 5) years

Then ATQ, 

x + 15 = 5 (x - 5)

x + 15 = 5x - 25

=> x = 10

 

Hence, Rajeev's present age = x = 10 years.

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47 26211
Q:

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence.

Answer

Given that, A+B = 60  and A = 2B.


Solving, We get A = 40, B = 20.


Five years their ages will be 45 and 25, so the sum of their ages will be 70.


 

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69 22895
Q:

The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class ?

A) 1:3 B) 2:3
C) 3:2 D) 3:1
 
Answer & Explanation Answer: B) 2:3

Explanation:

Let number of boys = x  , Let number of girls = y
Total numbers of students = x + y
(x + y) × 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3

 

 Ratio of boys and girls in the class is 2:3

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35 21060
Q:

When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ?

A) 50 yrs B) 60 yrs
C) 70 yrs D) 65 yrs
 
Answer & Explanation Answer: B) 60 yrs

Explanation:

Let the Father be x years when he died

Average Age 10 years ago be A

Total Age 10 years ago = 6*A

Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60

Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0

(6A +60 - x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60

Therefore we can conclude that the father was 60 years old when he died.

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56 19017
Q:

The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:

A) 10 B) 13
C) 15 D) 18
 
Answer & Explanation Answer: C) 15

Explanation:

Krish’s age = 3A and Vaibhav’s age = 5A


(3A+9)/(5A+9) = 3/4


=> 4 (3A + 9) = 3 (5A + 9)


=> A = 3


Therefore, Vaibhav’s age = 15 years.

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39 18536
Q:

Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :

A) 19 years B) 17 years
C) 15 years D) data inadequate
 
Answer & Explanation Answer: D) data inadequate

Explanation:

Let Meena’s age = A.
Then Sivagami’s age = A + 2
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.

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48 18509
Q:

The ratio of the father's age to the son's age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?

Answer

Let father's age be 3x and son's age be x years




Father's age after 5 years = 3x + 5 = 26 years


Son's age after 5 years = x + 5 = 12 years


 Ratio of father's and son's ages = 26 : 12 = 13 : 6


 

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88 18183