# Bar Charts Questions

Q:

Study the given bar graph and pie chart to answer the following questions.

The bar graph shows the production (in thousand tonnes) of Wheat, Rice and Maize in different states.

The pie-chart shows the percentage of agricultural land in the given six states.

Productivity = $\inline \dpi{100} \frac{Total\: Production}{Area\: of\: agricultural\: land}$

1.The productivity of which state is the maximum ?

1. Bihar       2. Haryana     3. Punjab     4. UP       5. MP

2.The production of which state is the maximum ?

1. Bihar       2. MP         3. Haryana       4. UP       5. Punjab

3.The prodution of wheat in punjab is what per cent more than the production of Maize in odisha ?

1. 350%       2. 250%       3. 300%       4. 200%       5. 400%

4.What is the ratio of the production of Rice in Bihar to the production of Wheat in Haryana ?

1. 2:3           2. 3:2           3. 2:1           4. 1:1             5. 1:2

5.If MP exports 40% of Rice at the rate of Rs.30 per kg and UP exports 30% of Rice at the rate of Rs.32 per kg, then what is the ratio of the income from the exports ?

1. 65:48       2. 31:42       3. 43:54       4. 57:62       5. 1:2

Explanation : Productivity = $\inline \dpi{100} \fn_cm \frac{Toatal\: Production}{Area\: of \: agricultural\: land}$

Productivity of UP = $\inline \dpi{100} \fn_cm \frac{(35+30+25)\times 1000}{2lakh\times \frac{30}{100}}=\frac{90000}{60000}=1.5\: tonnes\: per\: sq.km$

Productivity of MP = $\inline \dpi{100} \fn_cm \frac{(30+32.5+27.5)\times 1000}{2lakh\times \frac{25}{100}}=\frac{90000}{50000}=1.8\: tonnes\: per\: sq.km$

Productivity of Bihar = $\inline \dpi{100} \fn_cm \frac{(22.5+25.5+27.5)\times 1000}{2lakh\times \frac{20}{100}}=\frac{75000}{40000}=1.875\: tonnes\: per\: sq.km$

Productivity of Odisha = $\inline \dpi{100} \fn_cm \frac{(22.5+15+10)\times 1000}{2lakh\times \frac{5}{100}}=\frac{47500}{10000}=4.75\: tonnes\: per\: sq.km$

Productivity of Haryana = $\inline \dpi{100} \fn_cm \frac{(25+35+30)\times 1000}{2lakh\times \frac{8}{100}}=\frac{90000}{16000}=5.625\: tonnes\: per\: sq.km$

Productivity of Punjab = $\inline \dpi{100} \fn_cm \frac{(40+30+35)\times 1000}{2lakh\times \frac{12}{100}}=\frac{105000}{24000}=4.375\: tonnes\: per\: sq.km$

$\inline \dpi{100} \fn_cm \therefore$ Productivity of Haryana is the maximum.

Explanation : Production of Punjab is maximum = 105000 tonnes

Explanation : Production of Wheat in Punjab = 40000 tones

Production of Maize in Odisha = 10000 tones

$\inline \dpi{100} \fn_cm \therefore$ Required % = $\inline \dpi{100} \fn_cm \frac{40000-10000}{10000}\times 100 = 300$%

Explanation : The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1

Explanation : Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = $\inline \dpi{100} \fn_cm 32500\times \frac{40}{100}\times 1000\times 30$ = Rs.39 crore

Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = $\inline \dpi{100} \fn_cm 30000\times \frac{30}{100}\times 1000\times 32$ = Rs.28.8 crore

$\inline \dpi{100} \fn_cm \therefore$ Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48

7156
Q:

The following chart represents the number of students who passed the CAT exam or the XAT exam or the CET exam or None of these exams. (Assume that there are no students who passed more than one exam.)

Number of students who qualified CAT/XAT/CET Exams

1.  Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared) ?

1. 2000               2. 2001               3. 2002               4. Cannot be determined

2. What was the percentage of students who succeeded in at least one of three exams in 2000 ?

1. 82.4%             2. 82.8%             3. 82.35%           4. 83.3%

3. What is the percentage increase in the number of students in 2002 over 2000 ?

1. 30%                 2. 17.64%           3. 117.6%           4. 85%

4. What is the percentage of students who cleared CAT in 2000 ?

1. 19.56%           2. 12.65%           3. 14.28%           4. 11.76%

Explanation -  Compare the respective pass percentage for three years : 2000, 2001 and 2002

$\inline \dpi{100} \frac{140\times 100}{170}< \frac{150\times 100}{180} \: \: and\: \: \frac{150\times 100}{180}> \frac{160\times 100}{200}$

= 82.35% < 83.33% and 83.33% > 80%

Explanation -  Total percentage of students who succeeded in at least one of three exams in 2000 = $\inline \dpi{100} \frac{140\times 100}{170}$ = 82.35 %

Explanation -  Total percentage increase in the number of students in 2002 over 2000 is = $\inline \dpi{100} \frac{30\times 100}{170}$ = 17.64 %

Explanation -  Total percentage of students who cleared CAT in 2000 = $\inline \dpi{100} \frac{20\times 100}{170}$= 11.76 %

1498
Q:

Study the following graph carefully and answer the questions that follow:

Water level of four major Rivers (in meters) in four different Months

1. what was the respective ratio between the level of River - C in September and the water level of River - B in June?

1. 91 : 101           2. 94 : 101           3. 51 : 103           4. None of these

2. If the danger level of all the four rivers is above 215 m, which river has not crossed the danger level in August but has crossed the danger level in July ?

1. River - A          2. River - B          3. River - C          4. River - D

3. What is the average water level of River - A in all the four months together ?

1. 224.50 m        2. 212.25 m        3. 210.75 m        4. 222.25 m

4. In which river and in which month respectively the water level is highest ?

1. River - C in August     2. River - D in September     3. River - B in July     4. River - D in August

5. If the water level of River - A in July is decreased by 20 percent, then what will be the water level of River - A in July ?

1. 156 m              2. 162 m              3. 164 m            4. 152 m

Explanation : The water level of River - C in September = 184 and water level of River - B in June = 202

Required ratio = 184 : 202   $\inline \dpi{100} \Rightarrow$92 : 101

Explanation : Average water level of River - A in all months =$\inline \dpi{100} \frac{196+205+230+212}{4}\: m$= 210.75 m

Explanation : Water level of River - A in July after decreasing =$\inline \dpi{100} 205\times \frac{80}{100}$      = 41 x 4 = 164m

950
Q:

The following bar graph indicates the production of sugar (in lakh tonnes) by three different sugar companies P, Q and R over years 2009 to 2013.

Production of Sugar by Companies P, Q and R during 2009 - 2013

1. The percentage increase in production of Company Q from the year 2009 to the year 2013 is :

1. 80%              2. 90%              3. 60%              4. 100%

2. The average production over the years 2009 - 2013 was maximum for the Company(ies):

1. Q                   2. P                   3. R                   4. P and R

3. The percentage rise or fall in production of Company Q as compared to the previous year is the maximum in the year :

1. 2011             2. 2010             3. 2013             4. 2012

4. The percentage of production of Company R to Production of Company Q is the maximum in the year

1. 2010             2. 2009             3. 2011             4. None of these

5. The ratio of the average production of Company P during the years 2011 to 2013 to the average production of Company Q for the same period is :

1. 23 : 25          2. 27 : 29          3. 15 : 17          4. 9 : 11

Explanation : Required Percentage =$\inline \dpi{100} \frac{100-50}{50}\times 100$= 100%

Explanation : The average production of P = $\inline \dpi{100} \frac{60+90+50+100+80}{5}$= 76

The average production of Q =$\inline \dpi{100} \frac{50+70+70+80+100}{5}$  = 74

The average production of R = $\inline \dpi{100} \frac{70+80+90+70+70}{5}$ = 76

Maximum average production = P and R both

Explanation : The percentage rise in 2010 =$\inline \dpi{100} \frac{70-50}{50}\times 100$ = 40%

The percentage rise in 2011 =$\inline \dpi{100} \frac{70-70}{70}\times 100$ = 0%

The percentage rise in 2012 = $\inline \dpi{100} \frac{80-70}{70}\times 100$= 14.28%

The percentage rise in 2013 =$\inline \dpi{100} \frac{100-80}{80}\times 100$ =25%

Explanation : The percentage of production of Company R to production of Company Q

in 2009 =$\inline \dpi{100} \frac{70}{50}\times 100$ = 140

in 2010 =$\inline \dpi{100} \frac{80}{70}\times 100$ = 114.28

in 2011 =$\inline \dpi{100} \frac{90}{70}\times 100$ = 128.57

in 2012 = $\inline \dpi{100} \frac{70}{80}\times 100$= 87.5

in 2013 =$\inline \dpi{100} \frac{70}{100}\times 100$ = 70

Explanation : Average production of company P during the years 2011 to 2013 =$\inline \dpi{100} \frac{50+100+80}{3}$ = $\inline \dpi{100} \frac{230}{3}$
Average production of company Q during the years 2011 to 2013 =$\inline \dpi{100} \frac{70+80+100}{3}$ = $\inline \dpi{100} \frac{250}{3}$