6
Q:

# Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in

 A) 6 days B) 12 days C) 4 days D) 3 days

Explanation:

Let x men can do the in 12 days and the required number of days be z

More men, Less days     [Indirect Proportion]

Less work, Less days     [Direct Proportion  ]

$\inline \fn_cm \left.\begin{matrix} Men & 2x:x\\ Work&1:\frac{1}{2} \end{matrix}\right\}::12:z$

$\inline \fn_cm \therefore (2x\times 1\times z)=(x\times \frac{1}{2}\times 12)$$\inline \fn_cm \Rightarrow 2xz=6x\Rightarrow z=3$

Q:

The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?

 A) 14th element B) 9th element C) 12th element D) 7th element

Explanation:

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

3 78
Q:

In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ?

 A) 18 B) 14 C) 22 D) 24

Explanation:

1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14
Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between them
So minimum no. of boys standing in the queue = 14

3 97
Q:

If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ?

 A) Rs. 175 B) Rs. 325 C) Rs. 340 D) Rs. 260

Explanation:

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

4 105
Q:

An industrial loom weaves 1.14 meters of cloth every second. Approximately, how much time will it take to weave 52 meters of cloth ?

 A) 29.32 sec B) 42.51 sec C) 39.25 sec D) 45.61 sec

Explanation:

Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in,

1.14 ----- 1

52.0 ------?

$\inline \fn_jvn \Rightarrow$  $\inline&space;\dpi{100}&space;\frac{52}{1.14}$ = 45.61 sec

3 350
Q:

If 36 men can do a piece of work in 25 hours, in how mwny hours will15 men do it?

 A) 40 B) 50 C) 60 D) 70

Explanation:

Let the required no of hours be x. Then

Less men , More hours    (Indirct Proportion)

$\inline&space;\fn_jvn&space;\therefore$  15:36 ::25:x  $\inline&space;\fn_jvn&space;\Leftrightarrow$ (15 x X)=(36 x 25)  $\inline&space;\fn_jvn&space;\Leftrightarrow$ $\inline&space;\fn_jvn&space;x=\frac{36\times&space;25}{15}=60$

Hence, 15 men can do it in 60 hours.