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Q:

In a certain code language 'allow children to play on the ground' is written as 'play allow on children the to ground' then how will  'the do open not electric touch wires ' be coded from that language?

A) not the electric do touch open wires B) do not touch the electric open wires
C) do not touch the open electric wires D) not the do electric touch open wires

Answer:   C) do not touch the open electric wires

Explanation:

For convenience , we assign numbers to each word :

allow  children  to  play  on  the  ground

   1         2      3    4      5    6       7

It has been coded as : 

play  allow  on  children  the  to  ground

  4       1     5        2       6    3      7

------------------------------------------------------------------------

Hence the given code is :

the  do  open  not  electric  touch  wires

 4     1      5     2       6         3       7

Now arranging them as 1 2 3 4 5 6 7, we have "do not touch the open electric wires'.

Hence, option (3) is correct answer. 

Q:

In a certain language, SUPERMAN is coded as TTQDSLBM. How is SPIDERMAN coded in that language ?

A) TOJCFQNZO B) TOJCFSLBM
C) TOJCFONZO D) TOJCOSLBM
 
Answer & Explanation Answer: A) TOJCFQNZO

Explanation:

There is two sequence.
S(odd) P(Even) I(odd) D(even) E(odd) R(even) M(odd) A(even) N(odd)
For odd sequence, we want to write next alphabet of that
and for even, we want to write previous alphabet of that.

TOJCFQNZO is the Answer.

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2 198
Q:

In a certain code language ‘ROUTINE’ is written as 'VMRGFLI'. How will 'CRUELTY' be written in that code language ?

A) UPVCZLR B) VPCVZRL
C) CVCPZRL D) VCPCZLR
 
Answer & Explanation Answer: B) VPCVZRL

Explanation:

ROUTINE IS 7 LETTER WORD.. (1st=R,2nd=O,3rd=U,4th=T,5th=I,6th=N,7th=E)
1st and 3rd letter interchanging. (UORTINE)
5th and 7th letter interchanging. (UORTENI)
1st letter shifting one after that (VORTENI)
2nd letter shifting two befor that (VMRTENI)
3rd letter remains same (VMRTENI)
4th letter
(total alphabets - current)+1
(26 - 20)+1= 7.(i.e) G (VMRGFNI)
5th letter shifting one after that (VMRGFNI)
6th letter shifting two befor that (VMRGFLI)
7th letter remains same (VMRGFLI
Like that,
CRUELTY IS 7 LETTER WORD.. (1st=C,2nd=R,3rd=U,4th=E,5th=L,6th=T,7th=Y)
1st and 3rd letter interchanging. (URCELTY)
5th and 7th letter interchanging. (URCEYTL)
1st letter shifting one after that (VRCEYTL)
2nd letter shifting two befor that (VPCEYTL)
3rd letter remains same (VPCEYTL)
4th letter
(total alphabets - current)+1
(26 - 5)+1= 22.(i.e) V (VPCVYTL)
5th letter shifting one after that (VPCVZTL)
6th letter shifting two befor that (VPCVZRL)
7th letter remains same (VPCVZRL).

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2 189
Q:

In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ?

A) 56 B) 58
C) 62 D) 64
 
Answer & Explanation Answer: A) 56

Explanation:

If we count letters till the end of the alphabet including that letter in reverse order then
Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1
G = 20 and O = 12 totaling 32
S = 8, H = 19 and E = 22 totaling 49

So
SOME = 8 + 12 + 14 + 22 = 56.

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3 302
Q:

In a certain encryption pattern, HARD is coded as 1357 and SOFT is coded as 2468, What will 21448 stand for ?

A) SHAFT B) SHOOT
C) RAFTS D) ROOTS
 
Answer & Explanation Answer: B) SHOOT

Explanation:

AS HARD is coded as "1357" and SOFT is coded as "2468"
So H is coded as 1, A as 3, R as 5, D as 7
and S as 2, O as 4, F as 6, T as 8

Now in 21448, go number by number
2 is the code for S
1 is the code for H
4 is the code for O
and
8 is the code for T

hence, 21448 will stand for SHOOT

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2 213
Q:

In a certain code language 'how many goals scored' is written as '5397'; 'many more matches' is written as '982'; and 'he scored five' is written as '163'. How is 'goals' written in that code language ?

A) 5 B) 7
C) 3 D) Data is not sufficient
 
Answer & Explanation Answer: D) Data is not sufficient

Explanation:

From the given data,
how many goals scored = 5397....(1)
many more matches = 982.....(2)
he scored five = 163.....(3)
from (1)&(2), many = 9 ....(4)
from (1)&(3), scored = 3 ....(5)
Using (4)&(5)in(1), we get goals = 5 or 7.

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