21
Q:

A certain sum is to be divided between A and B so that after 5 years the amount received by A is equal to the amount received by B after 7 years. The rate of interest is 10%, interest compounded annually. Find the ratio of amounts invested by them. 

Additional Details

please solve this

 

Answer:
Q:

Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ?

A) 6.5% B) 6%
C) 5% D) 4.5%
 
Answer & Explanation Answer: C) 5%

Explanation:

C.I = 

594.5 = 

 % .

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3 109
Q:

The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ?

A) Rs. 1100 B) Rs. 5500
C) Rs. 1400 D) Rs. 4120
 
Answer & Explanation Answer: A) Rs. 1100

Explanation:

Let the sum be Rs.x. Then, 

=> x =5500

sum = Rs. 5500.

So, S.I = Rs.

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2 210
Q:

There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ?

A) Rs. 5422 B) Rs. 5489
C) Rs. 3972 D) Rs. 6145
 
Answer & Explanation Answer: C) Rs. 3972

Explanation:

Let p = Rs. 100.
Then, S.I is Rs. 50 and time = 5 years.

 = 10% p.a.

Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.
C.I. = Rs. = Rs. 

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4 205
Q:

The minimum number of half years in which a sum of money kept at 60% compound interest will be quadrupled is ?

A) 2 B) 4
C) 3 D) 6
 
Answer & Explanation Answer: D) 6

Explanation:

Let us assume Amount be 100 Rs and we calculate in CI

First year 60% of 100 = 60 amount (100+60) is 160

Second year 60% of 160 = 96 amount (160+96) is 256

Third year 60% of 256 =153.6 amount (256+153.6) is 409.6

Here the Amount of 100 Rs is quadrapled in 3 years.

One year contains 2 half years

Three year has 6 half years.

 It takes 6 half years.

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10 314
Q:

A sum is being lent at 20 % per annum compound interest.what is the ratio of increase in amount of 4th year to 5th year?

A) 4:5 B) 5:4
C) 5:6 D) can't be determined
 
Answer & Explanation Answer: C) 5:6

Explanation:

\inline \frac{p\left ( 1+\frac{r}{100} \right )^4}{p\left ( 1+\frac{r}{100} \right )^5}=\frac{1}{\left ( 1+\frac{r}{100} \right )}

                    = \inline \frac{100}{100+r}=\frac{100}{120}  = \inline \frac{5}{6}

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