0
Q:

Example:Given an amount needed(future value) of $3300 in 4 years at an interest rate of 11% compounded anually,Find the present value and the amount of interest earned

A) 1126.19 B) 1237
C) 2863 D) 1892

Answer:   A) 1126.19



Explanation:

M=P(1+i)^n

Q:

Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years?

A) Rs. 704 B) Rs. 854
C) Rs. 893 D) Rs. 914
 
Answer & Explanation Answer: A) Rs. 704

Explanation:

We know that,

S.I. = PTR100 P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1

From given data, P = Rs. 8625

Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

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3 312
Q:

Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years? 

A) Rs. 3845 B) Rs. 4826
C) Rs. 5142 D) Rs. 4415
 
Answer & Explanation Answer: B) Rs. 4826

Explanation:

We know the formula for calculating

The compound interest C = P1 + r100n - 1 where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then C = 65001 + 101002 x 1 + 201002 - 1= 6500 x 18562500= 65 x 185625

C = Rs. 4826.

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6 215
Q:

What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly?

A) Rs. 1.80 B) Rs. 2.04
C) Rs. 3.18 D) Rs. 4.15
 
Answer & Explanation Answer: B) Rs. 2.04

Explanation:

Compound Interest for 1 12 years when interest is compounded yearly = Rs.(5304 - 5000)


Amount after 112 years when interest is compounded half-yearly 


Compound Interest for 1 12 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)


Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

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4 295
Q:

The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is Rs. 56. Then the sum is :

A) Rs. 3680 B) Rs. 2650
C) Rs. 1400 D) Rs. 1170
 
Answer & Explanation Answer: C) Rs. 1400

Explanation:

We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by C.In - S.In = PR100n

Here n = 2 years, R = 20%, C.I - S.I = 56

56 = P201002=> P = 56 x 52=> P = 56 x 25=> P = Rs. 1400

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9 348
Q:

Find the compound interest on Rs. 2680 at 8% per annum for 2 years ?

A) Rs. 664.21 B) Rs. 548.68
C) Rs. 445.95 D) Rs. 692.57
 
Answer & Explanation Answer: C) Rs. 445.95

Explanation:

We know Compound Interest = C.I. = P1+r100t - 1

Here P = 2680, r = 8 and t = 2

C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225

= (2680 x 52 x 2)/625

= 445.95

 

Compound Interest = Rs. 445.95

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9 420
Q:

The compound interest on Rs. 8000 for 3 year at 10% p.a. is

A) 2648 B) 2145
C) 2587 D) 2784
 
Answer & Explanation Answer: A) 2648

Explanation:

8000 × 33.1% = 2648

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12 630
Q:

Compound interest on a certain sum of money at 20% per annum for 2 years is Rs.5995. What is the SI on the same money at 8% per annum for 6 years ?

A) Rs. 5989 B) Rs. 6540
C) Rs. 7844 D) Rs. 6789
 
Answer & Explanation Answer: B) Rs. 6540

Explanation:

Given C.I = 5984, R = 20% , T = 2yrs

 C.I = P1+201002-1

 

5984 = 

 

=> P = (5995x25)/11

 

P = Rs. 13625

 

Now S.I = PTR/100

 

SI = (13625 x 8 x 6)/100 = Rs. 6540

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20 1527
Q:

At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ?

A) 5% B) 6%
C) 4% D) 3%
 
Answer & Explanation Answer: A) 5%

Explanation:

Given compound interest for 3 years = Rs. 1513.2

 

and simple interest for 5 years = Rs. 2400

 

Now, we know that  C.I = P1+R100n - 1

 

=> 1513.2 = P1+R1003 - 1 ...........(A)

 

And S.I = PTR/100

 

=> 2400 = P5R/100 ..................(B)

 

By solving (A) & (B), we get

 

R = 5%.

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14 1827