# AIEEE Questions

Q:

What was the day on 15th august 1947 ?

 A) Friday B) Saturday C) Sunday D) Thursday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

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Q:

Tea worth of Rs. 135/kg & Rs. 126/kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be____?

 A) Rs. 169.50 B) Rs.1700 C) Rs. 175.50 D) Rs. 180

Explanation:

Since first second varieties are mixed in equal proportions, so their average price = Rs.$\inline \fn_jvn \small \left ( \frac{126+135}{2} \right )$ = Rs.130.50

So, Now the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say Rs. 'x' per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find 'x'.

Cost of 1 kg tea of 1st kind         Cost of 1 kg tea of 2nd kind

x-153/22.50 = 1  => x - 153 = 22.50  => x=175.50.

Hence, price of the third variety = Rs.175.50 per kg.

47 35337
Q:

The diagonal of the floor of a rectangular closet is 7$\fn_jvn \frac{1}{2}$ feet. The shorter side of the closet is 4$\fn_jvn \frac{1}{2}$ feet. What is the area of the closet in square feet?

 A) 9 B) 18 C) 27 D) 36

Explanation:

Other side = $\inline \sqrt{\left ( \frac{15}{2} \right )^{2}-\left ( \frac{9}{2} \right )^{2}}$ = $\inline \sqrt{\frac{225}{4}-\frac{81}{4}}$ = $\inline \sqrt{\frac{144}{4}}$ = 6 ft

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

0 4618
Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

 A) 25 W B) Both C) 100 W D) Neither

Explanation:

Resistances of both the bulbs are

$R_{1}=\frac{V^{2}}{P_{1}}=\frac{220^{2}}{25}$

$R_{2}=\frac{V^{2}}{P_{2}}=\frac{220^{2}}{100}$

Hence  $R_{1}>&space;R_{2}$

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

Filed Under: Physics
Exam Prep: AIEEE

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Q:

There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

 A) 105 B) 7! x 6! C) 7!/5! D) 420

= 7 x $\inline \fn_jvn \small \frac{6x5}{2}$ x 1