# AIEEE Questions

Q:

What was the day on 15th august 1947 ?

 A) Friday B) Saturday C) Sunday D) Thursday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

455 74001
Q:

The diagonal of the floor of a rectangular closet is 7$\fn_jvn \frac{1}{2}$ feet. The shorter side of the closet is 4$\fn_jvn \frac{1}{2}$ feet. What is the area of the closet in square feet?

 A) 9 B) 18 C) 27 D) 36

Explanation:

Other side = $\inline \sqrt{\left ( \frac{15}{2} \right )^{2}-\left ( \frac{9}{2} \right )^{2}}$ = $\inline \sqrt{\frac{225}{4}-\frac{81}{4}}$ = $\inline \sqrt{\frac{144}{4}}$ = 6 ft

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

0 3876
Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

 A) 25 W B) Both C) 100 W D) Neither

Answer & Explanation Answer: A) 25 W

Explanation:

Resistances of both the bulbs are

$R_{1}=\frac{V^{2}}{P_{1}}=\frac{220^{2}}{25}$

$R_{2}=\frac{V^{2}}{P_{2}}=\frac{220^{2}}{100}$

Hence  $R_{1}>&space;R_{2}$

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

Filed Under: Physics
Exam Prep: AIEEE

32 3691
Q:

There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

 A) 105 B) 7! x 6! C) 7!/5! D) 420

Explanation:

Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,

Then, 7C1 x 6C2 x 4C4
= 7 x $\inline \fn_jvn \small \frac{6x5}{2}$ x 1
= 7 x 15 = 105.

7 2577
Q:

What was the day of the week on 17th June, 1998 ?

 A) Monday B) Tuesday C) Wednesday D) Friday

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March. April. May. June.
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.