Chemistry Questions

Flourine is the most electro negative element due to its small atomic radius .It also has the tendency to accept an electron to complete octet configuration

In this chemical reaction chlorine change oxidation number from 0 to -1 (reduction) and bromine change oxidation number from -1 to 0 (oxidation).

Chlorine is stronger oxidation reagent than bromine.

In VIIA or group 17 (halogen elements) there are six elements: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At) and tennessin(Ts).

They have high electronegativity because they have seven valence electrons in their outermost energy level, so they can gain an electron to have the octet rule.  

Going down in the group, element are weaker oxidazing reagent and less reactive.

Yes, all the given statements are NOT true about electrons and atomic orbitals.

True statements are ::

An orbital can contain a maximum of two electrons.

An atom’s lowest energy level has only one orbital.

An electron has different amount of energies in all orbitals.

Hybridisation of iodine is sp3d3

So, the structure is pentagonal bipyramid.

Bond Order  = 1/2[ Nb - Na]

where

Nb = Number of electrons in bonding molecular orbitals.

Na = Number of Electrons in antibonding molecular orbitals

Bond Order of N2⁺:

Total number of electrons: 13

Electronic Configuration= :σ1s² σ*1s² σ2s² σ*2s² π 2py² [π2pz² σ2px1 ]

Bond Order = [9-4]/2 = 5/2 = 2.5.