Bank PO Questions and Answers with Explanation, Job Roles

Q:

Missing Letter Challenge

A) I	B) M
C) P	D) L

Answer & Explanation Answer: D) L

Explanation:

Here the letters follow the rule (AxZ)+(A+Z)

The number corresponding to the letters are used in the rule

A=1, Z=26 => 26x1 + 1 + 26 = 26+27 = 53 = 053

(LxP)+(L+P) = (12 x16) + 12 + 16 = 192+28 = 220

Similarly (11x12) + 11 + 12 => 132 + 23 = 155

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Filed Under: Missing letters puzzles
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33 8182

Q:

The product of two positive numbers is p. If each of the numbers is increased by 2, the new product is how much greater than twice the sum of the two original numbers ?

A) p times	B) 2p times
C) (p + 4) times	D) (2p + 3) times

Answer & Explanation Answer: C) (p + 4) times

Explanation:

Let the two no's be a and b;
Given product of the no's is p = ab;
If the each nos is increased by 2 then the new product will be
(a+2)(b+2) = ab + 2a + 2b + 4
= ab + 2(a+b) + 4
= p + 2(a+b) + 4
Hence the new product is (p+4) times greater than twice the sum of the two original numbers.

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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11 8182

Q:

ANBC full form is?

Answer

ANBC Full Form is Adjusted Net Bank Credit.

ANBC refers to Adjusted Net Bank Credit, is Net Bank Credit added to investments made by banks in non-SLR bonds (in held-to-maturity) or it is the credit equivalent of off-balance - sheet exposures, whichever is higher.

Net Bank Credit = Outstanding bank credits in India (-) Bills rediscounted with RBI/approved financial institutions.

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Subject: Indian Economy Exam Prep: GATE , CAT , Bank Exams
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17 8178

Q:

If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:

A) Rs. 408	B) Rs. 204
C) Rs. 412	D) Rs. 220

Answer & Explanation Answer: B) Rs. 204

Explanation:

Given ratio = 1/2:2/3:3/4 = 6:8:9

1st part = 782 x 6/23 = Rs. 204.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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10 8178

Q:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

A) 16	B) 17
C) 18	D) 19

Answer & Explanation Answer: D) 19

Explanation:

$17 \frac{4}{7} + 13 \frac{2}{12} - ? = 11 \frac{2}{3}$

$\frac{123}{7} + \frac{158}{12} - ? = \frac{35}{3}$

=> $? = \frac{123}{7} + \frac{158}{12} - \frac{35}{3}$

=> ? = $\frac{1476 + 1106 - 980}{84}$

=> ? = 19.07

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 8175

Q:

A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?

A) 47	B) 46
C) 37	D) 35

Answer & Explanation Answer: C) 37

Explanation:

The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 368/16 = 23
Number of cans of Pepsi = 80/16 = 5
Number of cans of Sprite = 144/16 = 9
The total number of cans required = 23 + 5 + 9 = 37 cans.

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Filed Under: HCF and LCM
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31 8171

Q:

The Most Abundant Rare Gas in the Atmosphere is

A) Xe	B) He
C) Ne	D) Ar

Answer & Explanation Answer: D) Ar

Explanation:

Argon is most the most abundant Rare Gas in the atmosphere. Its elemental symbol is Ar.

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Filed Under: Chemistry
Exam Prep: AIEEE , Bank Exams
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8 8156

Q:

If $a^{2} + b^{2} = c^{2}$ , then $\frac{1}{l o g_{c + a} (b)} + \frac{1}{l o g_{c - a} (b)} = ?$

A) 1	B) 2
C) 4	D) 8

Answer & Explanation Answer: B) 2

Explanation:

Given $a^{2} + b^{2} = c^{2}$

Now $\frac{1}{\log_{c + a} (b)} + \frac{1}{\log_{c - a} (b)}$

= $\log_{b} (c + a) + \log_{b} (c - a)$

= $\log_{b} (c^{2} - a^{2})$

= $2 \log_{b} (b) = 2$

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Filed Under: Logarithms
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30 8152

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