# Bank PO Questions

A) 116% | B) 166.66% |

C) 60% | D) 100% |

Explanation:

Let the cost price of 1-liter pure milk be Re.1, then

$\left\{\begin{array}{l}6liters\left(milk\right)\to C.P=Rs.6\\ 2liters\left(water\right)\to C.P=Rs.0\end{array}\right.\to CP=Rs.6only$

8 litre mixture =>

SP => 8 x 2 = Rs. 16

Profit % = $\frac{16-6}{6}x100=\frac{1000}{6}=\mathbf{166}\mathbf{.}\mathbf{66}\mathbf{\%}$

A) 10000 | B) 20000 |

C) 40000 | D) 50000 |

Explanation:

Let sum=Rs.x

C.I. when compounded half yearly = $\left[x{\left(1+\frac{10}{100}\right)}^{4}-x\right]=\frac{4641}{10000}$

C.I. when compounded annually =$\left[x{\left(\frac{20}{100}\right)}^{2}-x\right]=\frac{11}{25}$

$\frac{4641}{10000}x-\frac{11}{25}x=482$

=> x=20000

A) 2109 | B) 3109 |

C) 4109 | D) 6109 |

Explanation:

Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.

Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]

=Rs. [8000 * (23/20) * (23/20) * (21/20)]

= Rs. 11109. .

:. C.I. = Rs. (11109 - 8000) = Rs. 3109.

A) Minicoy and Amindiv | B) Minicoy and Maldives |

C) Little Andaman and car Nicobar | D) South Andaman and Little Andaman |

Explanation:

Duncan Passage is a strait in the Indian Ocean. It is about 48 km wide.

It separates Rutland Island to the north, and Little Andaman to the south.

West of Duncan Passage is the Bay of Bengal, east is the Andaman Sea.

A) 110 | B) 120 |

C) 130 | D) 140 |

Explanation:

let length = x and breadth = y then

2(x+y) = 46 => x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

=> x²+y²+2xy= 529

=> 289+ 2xy = 529

=> xy = 120

area = xy = 120 sq.cm

51 + 52 + 53 + ...........+ 100

= (1 + 2 + 3 + .... + 100) - (1 + 2 + 3 + ...... + 50)

= **It is in the form of $\frac{n(n+1)}{2}seriessummation$**

= n1 = 100 , n2 = 50

=$\left[\frac{{\displaystyle 100\left(100+1\right)}}{{\displaystyle 2}}\right]-\left[\frac{50\left(50+1\right)}{2}\right]$

= **(5050 - 1275) = 3775**

A) 11pm | B) 12pm |

C) 1pm | D) 2pm |

Explanation:

Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.

Now 23 hrs 44 min. of this clock = 24 hours of correct clock.

356/15 hrs of this clock = 24 hours of correct clock

89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.

= 90 hrs of correct clock.

So, the correct time is 11 p.m.

A) 30 | B) 40 |

C) 50 | D) 60 |

Explanation:

Let the side of the square(ABCD) be x meters.

Then, AB + BC = 2x metres.

AC = $\sqrt{2x}$ = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % =$\frac{0.59x}{2x}*100$ = 30% (approx)