# Bank PO Questions

A) 1:1 | B) 1:2 |

C) 1:3 | D) 1:4 |

Explanation:

Let the side of the square be x. Then, its diagonal =

Radius of incircle =

Radius of circum circle=

Required ratio =

A) 110 | B) 120 |

C) 130 | D) 140 |

Explanation:

let length = x and breadth = y then

2(x+y) = 46 x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

x²+y²+2xy= 529

289+ 2xy = 529

xy = 120

area = xy = 120 sq.cm

A) 20 | B) 25 |

C) 30 | D) 35 |

Explanation:

Let breadth = x m

Then, length = (x+5)m

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25

A) 136 | B) 236 |

C) 336 | D) 436 |

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

Area of triangle ABC =

= = 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Area of the park = (60 x 40) = 2400

Area of the lawn = 2109

Area of the crossroads = (2400 - 2109) = 291

Let the width of the road be x metres. Then,

(x - 97)(x - 3) = 0

x = 3.