Bank PO Questions


Q:

If each side of a square is increased by 25%, find the percentage change in its area?

A) 65.25 B) 56.25
C) 65 D) 56
 
Answer & Explanation Answer: B) 56.25

Explanation:

let each side of the square be a , then area = a x a

As given that The side is increased by 25%, then

New side =  = 

New area = 

increased area= 

Increase %=  % = 56.25%

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Q:

A clock is set right at 8 a.m. The clock gains 10 minutes in 24 hours will be the true time when the clock indicates 1 p.m. on the following day?

A) 48 min. past 12. B) 46 min. past 12.
C) 45 min. past 12. D) 47 min. past 12.
 
Answer & Explanation Answer: A) 48 min. past 12.

Explanation:

Time from 8 a.m. on a day to 1 p.m. on the following day = 29 hours.

24 hours 10 min. of this clock = 24 hours of the correct clock.

 hrs of this clock = 24 hours of the correct clock.

29 hours of this clock =  hrs of the correct clock

= 28 hrs 48 min of the correct clock.

Therefore, the correct time is 28 hrs 48 min. after 8 a.m.

This is 48 min. past 12.

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Q:

If log 2 = 0.3010 and log 3 = 0.4771, the values of log5 512 is

A) 2.875 B) 3.875
C) 4.875 D) 5.875
 
Answer & Explanation Answer: B) 3.875

Explanation:

ANS:      log5512 = {\color{Black} \frac{\log 512}{\log 5}}  =  {\color{Black} \frac{\log 2^{9}}{\log (\frac{10}{2})}}  ={\color{Black} \frac{9\log 2}{\log10-\log 2 }} ={\color{Black} \frac{(9\times 0.3010)}{1-0.3010 }} ={\color{Black} \frac{2.709}{0.699 }} ={\color{Black} \frac{2709}{699 }} =3.876

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Q:

At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?

A) 54 past 4 B) (53 + 7/11) past 4
C) (54 + 8/11) past 4 D) (54 + 6/11) past 4
 
Answer & Explanation Answer: D) (54 + 6/11) past 4

Explanation:

4 o'clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min

50 min. spaces are gained in  min. or 

 Required time =  min. past 4.

 

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Q:

If the radius of a circle is decreased by 50%, find the percentage decrease in its area.

A) 55% B) 65%
C) 75% D) 85%
 
Answer & Explanation Answer: C) 75%

Explanation:

Let original radius = R.

New radius = 

Original area =  and new area = 

Decrease in area =  = 75%

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