7
Q:

A) 2 B) 5
C) 10 D) 15

Answer:   A) 2



Explanation:

\inline \fn_jvn {\color{Black}Let \; \log_{5}625\; \; =x}

\inline \fn_jvn {\color{Black}Then,5^{x}\; \; =625}

\inline \fn_jvn {\color{Black}\Rightarrow 5^{x}=5^{4}}

\inline \fn_jvn {\color{Black}\Rightarrow x=4}

\inline \fn_jvn {\color{Black}let\; \log_{2}(\log_{5}625)=y}

\inline \fn_jvn {\color{Black}then,\log_{2}4=y}

\inline \fn_jvn {\color{Black}\Rightarrow 2^{y}=4}

\inline \fn_jvn {\color{Black}\Rightarrow y=2}

Q:

Solve the equation   ?

A) -1/2 B) 1/2
C) 1 D) -1
 
Answer & Explanation Answer: A) -1/2

Explanation:

Rewrite equation as

Leads to 2x + 1 = 0 

Solve for x : x = -1/2

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3 198
Q:

If  = m, then  is equal to ?

A) 1/(1+2m) B) (1+2m)/2
C) 2m/(2m+1) D) (2m+1)/2m
 
Answer & Explanation Answer: B) (1+2m)/2

Explanation:

=
=

.

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6 429
Q:

If  , then 

A) 1 B) 2
C) 4 D) 8
 
Answer & Explanation Answer: B) 2

Explanation:

Given  

Now  = 

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7 452
Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048 B) 1.2040
C) 0.9840 D) 1.4521
 
Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, 

 

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11 1076
Q:

A fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 72 km/hr and speeds of slower train is 27 km/h. Also the length of faster ntrain is 100m, then find the length of the slower train if they are moving in the same direction.

A) 100 m B) 125 m
C) 150 m D) 175 m
 
Answer & Explanation Answer: C) 150 m

Explanation:

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15 1101