Find x if

$l o g_{\frac{1}{\sqrt{2}}} (\frac{1}{\sqrt{8}}) = l o g_{2} (4^{x} + 1) . l o g_{2} (4^{x + 1} + 4)$

A) 0	B) 1
C) 2	D) None of these

Answer: A) 0

Explanation:

By trial and error method, when we substitute

x = 0

Both LHS and RHS are equal.

Subject: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT
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Find x if log1218 = log24x + 1. log24x+1 + 4