Our solution:

Toss the coin twice.

Let TH, HT and TT correspond to the three choices.

And if you get HH, just repeat (so it takes 8/3 tosses on average).

BIASED COIN

If the coin was biased, TH and HT would occur with equal probability.

So you could assign THHT, HTTH and THTH to the three choices, with other 4-toss outcomes rejected.

Or you could assign HTT, THT and TTH to the three choices, with other 3-toss outcomes rejected.

A) Bill | B) John |

C) Todd | D) None |

Explanation:

Bill.

From the detectives code **0415 7140 7718**

Each 4 digits may represent one name

Here 7718 mirror image represent BILL.

A) 15 | B) 17 |

C) 10 | D) 6 |

Explanation:

Sum of numbers in the outer circle in before Arc should come in inner circle patterns in the clock wise direction next Arc.

i.e, 9+6 = 15 comes in next arc of inner circle

7+3 = 10 comes in next arc of inner circle

In the same way, 4+2 = 6 comes in place of '?'.

A) 27 | B) 36 |

C) 24 | D) 32 |

Explanation:

From the given conditions ,

only A = 27 yrs satisfies.

A) 16 | B) 18 |

C) 20 | D) 24 |

Explanation:

From first figure : each fig has the value of 20 => It has inside 4 figures => Each individual figure has the value of '5'

From second => Each Triangle has the value of '1' (bcoz it contains two in each)

From third => Figure star has the value of '4'

Then in fourth => 4 + 1 + 15 = 20

A) 5 | B) 10 |

C) 15 | D) 12 |

Explanation:

In the first figure, number of triangles are 5.

In the second, the figure becomes double then the number of triangles also doubles.

i.e, 10.