A) 5 | B) 15 |

C) -5 | D) 10 |

Explanation:

The pattern is -45, -35, -25, -15

The next number = 20-15= 5

A) 121 | B) 943 |

C) 462 | D) None |

Explanation:

Assume that the number is taken as XYZ.

Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9

Condition 2 => Y = X + Z

X Y Z

1 2 1

4 6 2

9 12 3 => (wrong because it is 4 digit.)

and 121 is not divisible by 2

The answer is 462.

A) 19 | B) 23 |

C) 17 | D) 15 |

Explanation:

If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29

If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29

If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27

common number is only 23 so it will be answer

A) 0 | B) 1 |

C) 3 | D) 5 |

Explanation:

All powers of 6 has 6 in units place so answer will definitely be 1.

A) Rs. 13 and Rs. 17 | B) Rs. 17 and Rs. 19 |

C) Rs. 23 and Rs. 17 | D) Rs. 13 and Rs. 19 |

Explanation:

If fares for cities L and M from K are x and y respectively, then

2x + 3y = 77 or 6x + 9y = 231...(1)

3x + 2y = 73 or 6x + 4y = 146...(2)

subtracting 2 from 1, we get

5y = 85

y = Rs. 17 => x = Rs. 13

A) 60 | B) 74 |

C) 82 | D) 58 |

Explanation:

Let,

no. of rice bowl = x

no. of dal bowl = y

no. of meat bowl = z

Then, x + y + z = 65 ....(1)

Also given that, 2x = 3y = 4z

substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),

We get x = 30.

As 1 rice bowl is shared between 2 guests,

Therefore, there are 60 guests.