A) 60% | B) 40% |

C) 50% | D) 30% |

Explanation:

Lets say shyam sells at 100,

Since Ram sells 25% cheaper than Shyam,

Therefor Ram sells at less than 25% of100 or 75 rs.

Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or

125% of x (say x price of bram )=75rs.

or 100% of x =60rs.

hence price of bram is 60rs.

now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.

Hence Brams Good is 40% cheaper than that of Shyam's good.

A) 45% | B) 60% |

C) 72% | D) 80% |

Explanation:

Here it is asked that **3 is what percent of 5**

Let 3 is** K percent **of 5.

=> K x 5/100 = 3

=> K = 300/5 = 60

Hence, **3 is 60% of 5.**

A) 96 | B) 100 |

C) 78 | D) 88 |

Explanation:

Given

$4\frac{4}{5}$ of 259.99 = ? % of 1247.9

24/5 x 260 = ? x 1248/100

? = 1248 x 100/1248

**? = 100.**

A) 35 | B) 55 |

C) 75 | D) 45 |

Explanation:

In the question it is asked for 5% of 1500

5 x 1500/100 = 15 x 5 = 75.

Hence, **5% of 1,500 is equal to 75.**

A) 0.5 | B) 1 |

C) 4 | D) 0 |

Explanation:

80x900/100 + 256 x 4 x ? = 1331 - 99

720 + 1024 x ? = 1232

? = 1232 - 720/1024

? = 512/1024 = 0.5

**? = 0.5 **

A) 35 | B) 38 |

C) 42 | D) 44 |

Explanation:

what is 70 of 50 means 70% of 50

$\mathbf{\Rightarrow}\frac{\mathbf{70}\mathbf{}\mathbf{x}\mathbf{}\mathbf{50}}{\mathbf{100}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathbf{=}\mathbf{}\mathbf{7}\mathbf{}\mathbf{x}\mathbf{}\mathbf{5}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathbf{=}\mathbf{}\mathbf{35}$

Hence, **70 of 50 is 35.**

A) Rs. 2326 | B) Rs. 5876 |

C) Rs. 1741 | D) Rs. 3136 |

Explanation:

Let total amount = Rs. P

Total expenditure = (23 + 33 + 19 + 16)% of P = 91%ofP

Remaining money = (100 - 91)% of P = 9% of P

But given in the question that,

9% of P = 504

9p/100 = 504

=> P = 50400/9

=> P = Rs. 5600

Required money spent on Food & Insurance = 23 + 33 %

= 56% of 5600

= 56 x 5600/100 = 56 x 56 = **Rs. 3136 **

A) 23 | B) 92 |

C) 48 | D) 52 |

Explanation:

Total number of female members = 115

Let the number of males = x

Number of females = y

=> x + y = 115 ......(1)

According to the given data,

x + y(0.50) = 69 ......(2)

From (1) & (2), we get

0.5y = 46

=> y = 46 x 2 = 92

=> x = 115 - 92 = 23

Hence, required number of gentlemen in the family **= x = 23.**

A) Rs. 180 | B) Rs. 150 |

C) Rs. 120 | D) Rs. 240 |

Explanation:

Given 30% of 500

$\mathbf{=}\mathbf{}\frac{\mathbf{30}}{\mathbf{100}}\mathbf{}\mathbf{x}\mathbf{}\mathbf{500}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}=30\mathrm{x}5\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathbf{=}\mathbf{}\mathbf{150}$

Hence, **30% of Rs. 500 = Rs. 150.**