5 years ago average age of A,B,C,D = 45 years

5 years ago total age of A, B, C, D = 45 x 4 = 180 years

Total present age of A, B, C, D = 180 + 5x4 = 200 years

If E's present age is x years

years

A) 22 yrs | B) 21 yrs |

C) 20 yrs | D) 24 yrs |

Explanation:

Let Reena’s present age be 'K' yrs.

Given:{(K+3) x 4} - {(K-3) x 3)}

=> K = 21 yrs

So her present age is 21 yrs.

Then, her age after 1 year is 22 yrs.

A) 50 yrs | B) 47 yrs |

C) 45 yrs | D) 42 yrs |

Explanation:

Let age of retirement = S

so according to the given condition 25000(x-20)

=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)

= 30000 + 210000 + 30000S-990000

= 30000S - 750000

or 25000S - 500000 = 30000x - 750000

or 5000x = 250000

or S = 50 yrs.

A) 50 yrs | B) 25 yrs |

C) 72 yrs | D) 40 yrs |

Explanation:

Let the daughter age be 'x'

Therefore, Son age = 5x, Mother age = 25x, Person age = 50x.

Thus we get, x+5x+25x+50x = 81

81x = 81

x = 1

Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.

A) 8 yrs | B) 16 yrs |

C) 6 yrs | D) 4 yrs |

Explanation:

Let the age of the youngest child is 'X' years.

Then the child elder than the yongest is 'X + 3' yrs

Since each have 3yrs difference upto 5 children

And given that

=> X + X+3 + X+6 + X+9 + X+12 = 50

=> 5X + 30 = 50

=> X = 4 yrs.

A) 48 yrs | B) 42 yrs |

C) 40 yrs | D) 36 yrs |

Explanation:

Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , then

w+x+y = 43x3 = 129 ---(i) and

w+y+z = 49x3 = 147 ---(ii)

Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)

Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36