|A) 4||B) 8|
|C) 10||D) None|
Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.
We know that the sum of their ages is 50 .
so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50
=> x= 4
The youngest child is 4 years old.