A) 15 | B) 20 |

C) 25 | D) 30 |

Explanation:

Let number of hit shots be 'X'

Let number of miss shots be 'Y'

Given X + Y = 40....(1)

50X - 10Y = 500.....(2)

Solving 1 and 2, we get

X = 15 and Y = 25

Therefore, number of hits = 15

A) Rs. 1580 | B) Rs. 2200 |

C) Rs. 1785 | D) Rs. 1950 |

Explanation:

He sold 4 cycles for Rs. 8400

[It means each cycle price is Rs. 2100]

And again he sold 3 cycles for Rs. 1900 each

If he want to gain avg profit on each cycle is Rs. 320 per cycle.

So profit for 10 cycles is @ Rs.320 is,

10 x 320 = Rs. 3200

He already got Rs. 1850 profit by selling 7 cycles.

Now, remaining amount is 3200 - 1850 = 1350

So from remaining 3 cycles we want to get Rs. 1350 profit ,

1350/3 = 450

so he must sell remaining 3 cycles at Rs. 2200 each one.

A) 2 hrs 50 min | B) 3 hrs 25 min |

C) 3 hrs | D) 2 hrs 5 min |

Explanation:

Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 6/7.

Balance by the distance,

1 x t = (6/7)(t + 30)

7t = 6(t + 30)

we get t as,

t = 180 minutes = 3 hrs.

A) 264 | B) 284 |

C) 215 | D) 302 |

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22

13x/12 = x+22

x = 264

A) 55 | B) 105 |

C) 215 | D) 148 |

Explanation:

First line will cut all other 14, similarly second will cut 13, and so on

Total = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.