Missing letters puzzles Questions

Given series is A F Z U G L T _

Starts with A

A + 5 letters = F

go to end of alphabet= Z

Z - 5 letters = U

from F go one more to G + 5 letters = L

from U go one back to U, T - 5 letters = O

Second Method ::

Change the letters to their corresponding number.

A=1

B=2

C=3

...

Z=26

A F Z U G L T _

1 6 26 21 7 12 20 ?

Look at the pattern: the 1st and 3rd numbers = 27, 1+26

the 2nd and 4th numbers = 27, 6+21

the 5th and 7th numbers = 27,

so the 6 and 8th would also equal 27.

27 - 12 = 15,

so the letter is O.

Answer: D

Explanation:    The diagram contains 3 sets of 4 letters - one set of outer corner letters, one set of inner corner letters, and one set of letters on each side of the square. The numerical values of the letters in each set add up to 40.

Here the letters follow the rule (AxZ)+(A+Z)

The number corresponding to the letters are used in the rule

A=1, Z=26 => 26x1 + 1 + 26 = 26+27 = 53 =  053

(LxP)+(L+P) = (12 x16) + 12 + 16 = 192+28 = 220

Similarly (11x12) + 11 + 12 => 132 + 23 = 155 

Answer: V

Explanation:     Starting at the top left, and moving anti-clockwise around the figure, letters advance through the alphabet 5 letters at a time.

The Logic followed in the given puzzle is :

L x P = 12 x 16 = 192 (Alphabetical numbers of L & P)

P x T = 16 x 20 = 320 (Alphabetical numbers of P & T)

Similarly, K x () = 132 => () = 132/11 = 12 => L

Hence, the missing letter is L

13 x 2 = 26 => Z (opposite side)

12 x 2 = 24 => X (opposite side)

13 x 1 = 13 => M (opposite side)

12 x 1 = 12 => L (opposite side)

The logic in the given puzzle is 

Addition of numeric values of corresponding letters in the first three figures gives respective corresponding letter in fourth figure. 

i.e, A = 1 , W = 23 , B = 2 => 2 + 1 + 23 =26 = 'Z'

Similarly, L = 12, K = 11 , A = 1 => 1 + 11 + 12 = 24 = 'X'

Here the missing letter is 'X'.

Answer : F

Explanation :     In each group of 3 boxes, calculate the difference in numerical values between the top two letters, and add 1 to give the value of the letter in the lower box