Quantity of milk in the given mixture = lts

Quantity of water in this mixture = 20 - 15 = 5 lts

Let x litres of milk be added to given mixture to have the requisite ratio of milk and water

Then

15 + x =20

x = 5

Milk to be added = 5 litres

A) 175 | B) 165 |

C) 155 | D) 145 |

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

A) 108 | B) 107 |

C) 109 | D) 110 |

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109

A) 225 deg | B) 210 deg |

C) 205 deg | D) 245 deg |

Explanation:

Angle of triangle = 180 × 3/12

= 45 deg

Other angles of the triangle are = 60 deg, 75 deg

Angle of quadrilateral

= 360 - (45 + 60 + 75)

= 180 deg

Therefore, the four angles of the quadrilateral are 45, 60, 75 & 180 degrees.

Hence, the sum of largest and smallest angle of the quadrilateral are 180 + 45 = 225 deg.

A) 120 lit | B) 140 lit |

C) 110 lit | D) 150 lit |

Explanation:

To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.

=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres

However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.

i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.

Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

A) 10 | B) 15 |

C) 20 | D) 30 |

Explanation:

Let the three parts M, N, O.

Then, M:N = 2:3 and N:O = 5:8

= (5 x 3/5) : (8 x 3/5) = 3:24/5

M:N:O = 2:3:24/5

= 10:15:24 => N = 98 x 15/49 = 30.