4
Q:

Alloy A contains 40% gold and 60% silver. Alloy B contains 35% gold and 40% silver and 25% copper. Alloys A and B  are mixed in the ratio of 1:4 .What is the ratio of gold and silver in the newly formed alloy is?

A) 20% and 30% B) 36% and 44%
C) 25% and 35% D) 49% and 36%

Answer:   B) 36% and 44%



Explanation:

Assume the weight of alloy a is 100 kg

\inline \fn_jvn \therefore  The weight of alloy B is 400kg

\inline \fn_jvn \therefore               Gold          silver         copper

         A       40kg          60kg          0kg

         B      140kg         160kg        100kg

      total    180kg          220kg        100kg

\inline \fn_jvn \therefore Ratio of gold and silver in new alloy =\inline \fn_jvn \frac{180}{500}:\frac{200}{500}

                                                        = 36% :44%

Q:

Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?

A) 108 B) 107
C) 109 D) 110
 
Answer & Explanation Answer: C) 109

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109

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6 113
Q:

The ratio of the angles of a triangle is 3 : 4 : 5. The three angles of a quadrilateral is equal to three angles of this triangle. What is the sum of the largest angle and second smallest angle of the quadrilateral ?

A) 225 deg B) 210 deg
C) 205 deg D) 245 deg
 
Answer & Explanation Answer: A) 225 deg

Explanation:

Angle of triangle = 180 × 3/12

= 45 deg

Other angles of the triangle are = 60 deg, 75 deg

Angle of quadrilateral

= 360 - (45 + 60 + 75)

= 180 deg

Therefore, the four angles of the quadrilateral are 45, 60, 75 & 180 degrees.

Hence, the sum of largest and smallest angle of the quadrilateral are 180 + 45 = 225 deg.

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5 229
Q:

80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 

A) 120 lit B) 140 lit
C) 110 lit D) 150 lit
 
Answer & Explanation Answer: D) 150 lit

Explanation:

To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.

=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres

However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.

i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.

Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

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5 704
Q:

The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:

A) 10 B) 15
C) 20 D) 30
 
Answer & Explanation Answer: D) 30

Explanation:

Let the three parts M, N, O.
Then, M:N = 2:3 and N:O = 5:8
= (5 x 3/5) : (8 x 3/5) = 3:24/5

M:N:O = 2:3:24/5

= 10:15:24 => N = 98 x 15/49 = 30.

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4 843
Q:

Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ?

A) 600 B) 300
C) 150 D) 75
 
Answer & Explanation Answer: A) 600

Explanation:

1/2:1/3:1/4 = 6:4:3

As the difference is 3

=> 3/13x2600 = 600

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5 745