15
Q:

# Find the sub-triplicate ratio of 27:125

Q:

A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27,  what is the total amount  ?

 A) Rs. 159 B) Rs. 96 C) Rs. 147 D) Rs. 105

Explanation:

K : L : M = 100 : 45 : 30
= 20 : 9 : 6

Given L share is 27

=> 9  ------  27
35 ------  ?

=> 105

2 83
Q:

The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ?

 A) 4:5 B) 6:5 C) 3:2 D) 1:3

Explanation:

4:5
3:2
-------
=> 12:15:10

12:10

=> 6:5

3 140
Q:

What is the equivalent compound ratio of 5:6::7:10::6:5  ?

 A) 7 : 9 B) 9 : 7 C) 7 : 4 D) 7 : 10

Explanation:

Given 5:6 :: 7:10 :: 6:5

We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)

=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10

4 85
Q:

The incomes of two persons A and B are in the ratio 3:4. If each saves Rs.100 per month, the ratio of their expenditures is 1:2. Find their incomes  ?

 A) 200, 400 B) 100, 300 C) 100, 200 D) 150, 200

Explanation:

The incomes of A and B be 3P and 4P.

Expenditures = Income - Savings

(3P - 100) and (4P - 100)

The ratio of their expenditure = 1:2

(3P - 100):(4P - 100) = 1:2

2P = 100 => P = 50

Their incomes = 150, 200

1 123
Q:

In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ?

 A) 693 B) 741 C) 528 D) 654

Explanation:

Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)
= (1200)(30)(3) kg.

Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k

As the same provisions are available
=> (1200)(30)(3) = (1200 + x)(25)(2.5)

x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.