2
Q:

# Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of  Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?

 A) 21 years B) 16 years C) 8 years D) 12 years

Explanation:

Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then

x+x = y    -------(1)

and   $\inline&space;\fn_jvn&space;\frac{(x-3)}{(y-3)}=\frac{2}{7}&space;\:&space;\:&space;\Rightarrow&space;7x-2y=15$

Now, from  equation (1),

7x - 4x = 15  $\inline&space;\fn_jvn&space;\Rightarrow$  x = 5

So the age of Shipra 3 years hence will be 5+3 = 8 years

Q:

Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided?

 A) 7:1 B) 13:5 C) 15:7 D) 2:7

Explanation:

Maneela lent Rs. 8000 in two parts,

2 211
Q:

The ratio of male and female in a city is 7 : 8 respectively and percentage of children among male and female is 25 and 20 respectively. If number of adult females is 156800, what is the total population of the city?

 A) 4,12,480 B) 3,67,500 C) 5,44,700 D) 2,98,948

Explanation:

Let the total population be 'p'

Given ratio of male and female in a city is 7 : 8

In that percentage of children among male and female is 25% and 20%

=> Adults male and female % = 75% & 80%

But given adult females is = 156800

=> 80%(8p/15) = 156800

=> 80 x 8p/15 x 100 = 156800

=> p = 156800 x 15 x 100/80 x 8

=> p = 367500

Therefore, the total population of the city = p = 367500

4 110
Q:

Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ?

 A) 11 & 17 B) 7 & 17 C) 9 & 21 D) 13 & 23

Explanation:

Let the two numbers be x and y

Given x : y = 3 : 7 .....(1)

Now, x+6 : y+6 = 5 : 9 .....(2)

From (1), x = 3y/7

From (2), 5y - 9x = 24

=> 5y - 9(3y/7) = 24

=> y = 21

=> From(1), x = 9

Hence, the two numbers be 9 and 21

5 184
Q:

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

 A) 175 B) 165 C) 155 D) 145

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

14 360
Q:

Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?

 A) 108 B) 107 C) 109 D) 110

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109