A + B + C = 5625

4B + B = 5625

B = 1125

Also A + C = 4B = 4 x 1125 = 4500

Also

B = 2A - C

2A - C = 1125

Now solving A+C = 4500 and 2A-C = 1125

Then A = 1875 and C = 2625

A-B = 1875 - 1125 = Rs. 750

A) Rs. 5500 | B) Rs. 6000 |

C) Rs. 6200 | D) Rs. 6350 |

Explanation:

The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?

Ratio of increase of wages = 22:25

Ratio of decrease of labourers = 15:11

Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275

Final bill = Rs. 5000

For 275 ratio wages = Rs. 5000

For 1 ratio wages = 5000/275

For 330 ratio wages = 5000/275 x 330 = Rs. 6000

A) 7 : 12 | B) 8 : 13 |

C) 9 : 4 | D) 2 : 5 |

Explanation:

To get the solution that contains 1 part of milk and two parts of water,

they must be mixed in the ratio as

7x+6x/5y+11y = 1/2

26x = 16y

x/y = 16/26

x/y = 8/13

A) 11 | B) 7 |

C) 9 | D) 13 |

Explanation:

Here the number of cogs is inveresly proportional to number of revolutions

=> More cogs less revolution

=> 6 : 14 :: x : 21

=> (21x6)/14 = 9

A) 9 points | B) 10 points |

C) 11 points | D) 8 points |

Explanation:

a:b = 60:40

a:c = 60:45

c/a x a/b = 45/60 x 60/40 = 45/40 = 90/80

So C gives B => 10 points.

A) 125 | B) 155 |

C) 135 | D) 165 |

Explanation:

Ratio C1:C2 = 3:5 and C2:C3 = 7:11

So C1:C2:C3 = 21 : 35 : 55

Let the strength of three classes are 21x, 35x and 55x respectively, then

Given that 21x + 35x + 55x = 333

=> 111x = 333 or x=3

So strength of the class with highest number of students =55x = 55x3 = 165.