A) 1:3 | B) 2:1 |

C) 3:4 | D) 2:3 |

Explanation:

Let, B1 : B2 : B3 = 3x : 4x : 5x

again B1 : B2 : B3 = 5y : 4y : 3y

Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket

Therefore, 5x = 3y

Hence 3x : 4x : 5x => $\frac{9y}{5}:\frac{12y}{5}:\frac{15y}{5}$ = 9y:12y:15y

and 5y : 4y : 3y => 25x : 20x : 15x

Therfore, increment in first basket = 16

Increment in second basket = 8

Thus, required ratio = 16/8 = 2:1

A) 17 | B) 30 |

C) 26 | D) 32 |

Explanation:

$3\phantom{\rule{0ex}{0ex}}{3}^{2}+3=12\phantom{\rule{0ex}{0ex}}5\phantom{\rule{0ex}{0ex}}{\mathbf{5}}^{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{5}\mathbf{}\mathbf{=}\mathbf{}\mathbf{30}$

A) 6548 | B) 5667 |

C) 7556 | D) 8457 |

Explanation:

Let ratio of the incomes of Pavan and Amar be 4x and 3x

and Ratio of their expenditures be 3y and 2y

4x - 3y = 1889 ......... I

and

3x - 2y = 1889 ...........II

I and II

y = 1889

and x = 1889

**Pavan's income = 7556**

A) 7:1 | B) 13:5 |

C) 15:7 | D) 2:7 |

A) 4,12,480 | B) 3,67,500 |

C) 5,44,700 | D) 2,98,948 |

Explanation:

Let the total population be 'p'

Given ratio of male and female in a city is 7 : 8

In that percentage of children among male and female is **25%** and **20%**

=> Adults male and female % = **75% & 80%**

But given adult females is = 156800

=> **80%(8p/15) = 156800**

=> 80 x 8p/15 x 100 = 156800

=> p = 156800 x 15 x 100/80 x 8

=> p = 367500

Therefore, the total population of the city = **p = 367500**

A) 11 & 17 | B) 7 & 17 |

C) 9 & 21 | D) 13 & 23 |

Explanation:

Let the two numbers be x and y

Given x : y = 3 : 7 .....(1)

Now, x+6 : y+6 = 5 : 9 .....(2)

From (1), x = 3y/7

From (2), 5y - 9x = 24

=> 5y - 9(3y/7) = 24

=> y = 21

=> From(1), x = 9

Hence, the two numbers be **9** and **21**

A) 175 | B) 165 |

C) 155 | D) 145 |

Explanation:

Let the number of failed students be x

=> Number of passed students = 4x

So total number of students was 5x

From the given data,

If total number of students be 5x – 35

=> 4x-35-9/x+9 = 2/1

=> 4x – 44 = 2(x + 9)

=> 4x – 2x = 18 + 44

=> x = 31

Total number = 31×5

= 155

A) 108 | B) 107 |

C) 109 | D) 110 |

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109