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Q:

If $a^{2} \sec^{2} x - b^{2} \tan^{2} x = c^{2}$ then the value of $\sec^{2} x + \tan^{2} x$ is equal to (assume b2 ≠ a2 )

A) b2-a2+2c2b2+a2	B) b2+a2-2c2b2-a2
C) b2-a2-2c2b2+a2	D) b2-a2b2+a2+2c2

Answer & Explanation Answer: B) b2+a2-2c2b2-a2

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

Q:

The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest)

A) 19 years	B) 16 years
C) 18 years	D) 20 years

Answer & Explanation Answer: D) 20 years

Explanation:

Present total age of the members = 26(5) = 130 years.

Present age of the youngest member = 10 years

Present total age of the remaining four members = 130 -10 = 120 years

Their average age at the time of the birth of the youngest member = $\frac{[120 - (4 \times 10)]}{4}$ = 30 - 10 = 20 years.

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Filed Under: Problems on Ages
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

The following chart represents the number of students who passed the CAT exam or the XAT exam or the CET exam or None of these exams. (Assume that there are no students who passed more than one exam.)

Number of students who qualified CAT/XAT/CET Exams

1. Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared) ?

1. 2000 2. 2001 3. 2002 4. Cannot be determined

2. What was the percentage of students who succeeded in at least one of three exams in 2000 ?

1. 82.4% 2. 82.8% 3. 82.35% 4. 83.3%

3. What is the percentage increase in the number of students in 2002 over 2000 ?

1. 30% 2. 17.64% 3. 117.6% 4. 85%

4. What is the percentage of students who cleared CAT in 2000 ?

1. 19.56% 2. 12.65% 3. 14.28% 4. 11.76%

Answer

1. ANSWER : 2

Explanation - Compare the respective pass percentage for three years : 2000, 2001 and 2002

= (140 x 100)/170 < (150 x 100)/180 and (150 x 100)/180 > (160 x 100)/200

= 82.35% < 83.33% and 83.33% > 80%

2. ANSWER : 3

Explanation - Total percentage of students who succeeded in at least one of three exams in 2000 = (140 x 100)/170= 82.35 %

3. ANSWER : 2

Explanation - Total percentage increase in the number of students in 2002 over 2000 is = (30 x 100)/170 =17.64 %

4. ANSWER : 4

Explanation - Total percentage of students who cleared CAT in 2000 =(20 x 100)/170 = 11.76 %

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Subject: Bar Charts

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