H.C.F Search

Q:

If (x+a) is the H.C.F of $2 x^{2} + 5 x - 12 and x^{2} + x - 12$ then find the value of a.

A) -3	B) -2
C) 4	D) 5

Answer & Explanation Answer: C) 4

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

Q:

The product of two 2-digit numbers is 2160 and their H.C.F. is 12. The numbers are

A) (12, 60)	B) (72, 30)
C) (36, 60)	D) (60, 72)

Answer & Explanation Answer: C) (36, 60)

Explanation:

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Filed Under: HCF and LCM
Exam Prep: Bank Exams

Q:

H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is $2^{4} x 3^{5} x 5^{2} x 7^{2 . What is the third number?}$

A) 47628	B) 49874
C) 24157	D) 42146

Answer & Explanation Answer: A) 47628

Explanation:

hcf_of_three_numbers_3240,_3600_and_third_number_is_361542439249.jpg image

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

Q:

H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is :

A) 360	B) 180
C) 90	D) 120

Answer & Explanation Answer: B) 180

Explanation:

4 x 27 x 3125 = $2^{2} \times 3^{3} \times 5^{5}$ ;

8 x 9 x 25 x 7 = $2^{3} \times 3^{2} \times 5^{2} \times 7$

16 x 81 x 5 x 11 x 49 = $2^{4} \times 3^{4} \times 5 \times 11 \times 7^{2}$

H.C.F = $2^{2} \times 3^{2} \times 5$ = 180.

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Filed Under: HCF and LCM
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

Q:

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?

A) 13/125	B) 14/57
C) 11/120	D) 16/41

Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b.
We know that product of two numbers = Product of their HCF and LCM
Then, a + b = 55 and ab = 5 x 120 = 600.
=> The required sum = (1/a) + (1/b) = (a+b)/ab
=55/600 = 11/120

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Filed Under: HCF and LCM
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

Q:

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

A) 77	B) 88
C) 99	D) 110

Answer & Explanation Answer: A) 77

Explanation:

Product of numbers = 11 x 385 = 4235

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35

Now, co-primes with product 35 are (1,35) and (5,7)

So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)

Since one number lies 75 and 125, the suitable pair is (55,77)

Hence , required number = 77

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Filed Under: HCF and LCM

Q:

If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to

A) 55/601	B) 601/55
C) 11/120	D) 120/11

Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b . Then, a+b =55 and ab = 5 x 120 = 600.

Therefore, Required sum = $\frac{1}{a} + \frac{1}{b} = \frac{a + b}{a b} = \frac{55}{600} = \frac{11}{120}$

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Filed Under: HCF and LCM

Q:

The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is

A) 10	B) 46
C) 70	D) 90

Answer & Explanation Answer: A) 10

Explanation:

Let the numbers be x and (100-x).

Then, $x (100 - x) = 5 * 495$

=> $x^{2} - 100 x + 2475 = 0$

=> (x-55) (x-45) = 0

=> x = 55 or x = 45

The numbers are 45 and 55

Required difference = (55-45) = 10

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Filed Under: HCF and LCM

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