replacement Search

Q:

In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.

A) 16	B) 12
C) 10	D) 14

Answer & Explanation Answer: B) 12

Explanation:

Total balls = 40

Red balls = 18

Let green balls are x

Then, (18/40) × (

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT

Q:

During the last year, when your replacement hasn't shown up and your manager asked you to stay late, what percentage of the time have you stayed late?

Answer

Sample Answers :

(i) More Often 90%

(ii) 75% i stay when possible. sometimes there are other things that have to be done or plans that have already been made.

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Subject: Health Care Interview

Q:

How have you responded in the past when your replacement calls in sick and a substitute will take over an hour to come in?

Answer

Sample Answers :

(i) Upset but did not show it, that is the nature of the job, this things happen, the patients care takes priority.

(ii) I have not experienced this necessarily, but I have had my nurse mentor cancel on me because of a family emergency. In this situation I still attended my clinical and worked with a different nurse mentor. I quickly adapt to situations, which is an important quality in a nurse. In this situation I would stay until a substitute is able to come in. I would do this to ensure patient safety and maintain positive staff morale. It is important to recognize that getting sick is inevitable, and I will most likely be in the same situation one day and will need staff to pick up my shift.

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Subject: Health Care Interview

Q:

An urn contains 4 white 6 black and 8 red balls . If 3 balls are drawn one by one without replacement, find the probability of getting all white balls.

A) 5/204	B) 1/204
C) 13/204	D) None of these

Answer & Explanation Answer: B) 1/204

Explanation:

Let A, B, C be the events of getting a white ball in first, second and third draw respectively, then

Required probability = $P (A \cap B \cap C)$

= $P (A) P (\frac{B}{A}) P (\frac{C}{A \cap B})$

Now, P(A) = Probability of drawing a white ball in first draw = 4/18 = 2/9

When a white ball is drawn in the first draw there are 17 balls left in the urn, out of which 3 are white

$∴ P (\frac{B}{A}) = \frac{3}{17}$

Since the ball drawn is not replaced, therefore after drawing a white ball in the second draw there are 16 balls left in the urn, out of which 2 are white.

$∴ P (\frac{C}{A \cap B}) = \frac{2}{16} = \frac{1}{8}$

Hence the required probability = $\frac{2}{9} \times \frac{3}{17} \times \frac{1}{8} = \frac{1}{204}$

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Filed Under: Probability

Q:

From the 50 liters of milk, 5 liters of milk is taken out and after it 5 liters of water is added to the rest amount of milk. Again 5 liters of milk and water is drawn out and it was replaced by 5 liters of water. If this process is continued similarly for the third time, the amount of milk left after the third replacement:

A) 45L	B) 36.45L
C) 40.5L	D) 42.5L

Answer & Explanation Answer: B) 36.45L

Explanation:

General Formula:

Final or reduced concentration = initial concentration x ${(1 - \frac{a m o u n t b e i n g r e p l a c e d i n e a c h o p e r a t i o n}{t o t a l a m o u n t})}^{n}$

where n is the number of times the same operation is being repeated. The "amount being replaced" could be pure or mixture as per the case. similarly ,"total amount" could also be either pure or mixture. Here amount being replaced denotes the quantity which is to be withdrawn in each time.

Therefore, $50 \times {(1 - \frac{5}{50})}^{3}$

= 36.45 L

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Filed Under: Alligation or Mixture

Q:

You are scheduled to leave at 6 pm. Your replacement worker doesn't show up. What would you do?

Answer

If he was unable to make his shift, I would find a replacement, and stay until the replacement came in.

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Subject: Customer Service

Q:

Payments of $2000 and $1000 were originally scheduled to be paid one year and five years, respectively, from today. They are to be replaced by a $1500 payment due four years from today, and another payment due two years from today. The replacement stream must be economically equivalent to the scheduled stream. What is the unknown payment, if money can earn 7% compounded semiannually?

A) 1548	B) 1348
C) 1648	D) 1748

Answer & Explanation Answer: C) 1648

Explanation:

FV1 = Future value of $2000, 1 year later
= PV (1+ i)^n

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?

A) 1/6	B) 1/3
C) 1/2	D) 1/4

Answer & Explanation Answer: C) 1/2

Explanation:

P(odd) = P (even) = $\frac{1}{2}$ 1(because there are 50 odd and 50 even numbers)

Sum or the three numbers can be odd only under the following 4 scenarios:

Odd + Odd + Odd = $\frac{1}{2} * \frac{1}{2} * \frac{1}{2}$ = $\frac{1}{8}$

Odd + Even + Even = $\frac{1}{2} * \frac{1}{2} * \frac{1}{2}$ = $\frac{1}{8}$

Even + Odd + Even = $\frac{1}{2} * \frac{1}{2} * \frac{1}{2}$ = $\frac{1}{8}$

Even + Even + Odd = $\frac{1}{2} * \frac{1}{2} * \frac{1}{2}$ = $\frac{1}{8}$

Other combinations of odd and even will give even numbers.

Adding up the 4 scenarios above:

= $\frac{1}{8}$ + $\frac{1}{8}$ + $\frac{1}{8}$ + $\frac{1}{8}$ = $\frac{4}{8}$ = $\frac{1}{2}$

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Filed Under: Probability

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