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Q:

A rectangular swimming pool of length 30 m and breadth 15 m has a uniformly sloping floor. It is 1 m in depth on one end of its length and 2 m at the other. How much water is needed to completely fill this pool?

A) 1350 cubic mts	B) 2025 cubic mts
C) 675 cubic mts	D) 2700 cubic mts

Answer & Explanation Answer: C) 675 cubic mts

Explanation:

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Filed Under: Area
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Q:

A rectangular swimming pool of length 20 m and breadth 10 m has a uniformly sloping floor. It is 1 m in depth on one end of its length and 3 m at the other. How much water is needed to completely fill this pool? (Take π = 22/7)

A) 800 cubic metres	B) 300 cubic metres
C) 480 cubic metres	D) 400 cubic metres

Answer & Explanation Answer: D) 400 cubic metres

Explanation:

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Filed Under: Area
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Q:

A car accelerates uniformly from 18 kmph to 72 kmph in 5 s. The acceleration of the car (in m/sq.s) is:

A) 3	B) 5
C) 6	D) 7

Answer & Explanation Answer: A) 3

Explanation:

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Filed Under: Physics

Q:

A uniformly moving train of length 480 m takes 3 minutes to completely cross a platform. If the same train, with the same speed crosses a pole completely in 30 sec, then the length of the platform is -

A) 1 km	B) 600 m
C) 4.8 km	D) 1.2 km

Answer & Explanation Answer:

Explanation:

Let length of platform be ‘y’metres.

Then, at the platform,Distance travelled = y + (length of train) = (y + 480)m

Then, Speed of train = (y + 480)m / (3x60) sec = (y+480)/180 ...(1)

Also, at the pole,Distance travelled = length of train = 480m

Then, Speed of train = 480m / 30sec = 16 m/s ...(2)

Equating eq.(1) & eq.(2), we get,

(y+480)/180 = 16(y+480) = 16 x 180 = 2880

y = 2880 –480 = 2400m or 2.4 km long platform.

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Filed Under: Problems on Trains
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Q:

A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ?

A) 12 p.m. on Wednesday	B) 2 p.m. on Thursday
C) 3 p.m. on Thursday	D) 2 p.m. on Wednesday

Answer & Explanation Answer: B) 2 p.m. on Thursday

Explanation:

Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.
= 170 hours.
The watch gains = (2 + 4 x 4/5) min
= 34/5 min. in 170 hrs.
Now, 34/5 min are gained in 170 hrs.
Then, 2 min are gained in (170 x 5/34 x 2) hrs.
Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.

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Filed Under: Clocks
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Q:

A watch which gains uniformly is 2 minutes low at noon on monday and is 4 min.48 sec fast at 2 p.m on the following monday. when was it correct ?

A) 2 p.m on Tuesday	B) 2 p.m on Wednesday
C) 3 p.m on Thursday	D) 1 p.m on Friday

Answer & Explanation Answer: B) 2 p.m on Wednesday

Explanation:

Time from 12 p.m on monday to 2 p.m on the following monday = 7 days 2 hours = 170 hours

Therefore, The watch gains $(2 + 4 \frac{4}{5})$ min. or 34/5 min. in 170 hrs.

Now, 34/5 min. are gained in 170 hrs.

Therefore, 2 min are gained in $(170 \times \frac{5}{34} \times 2)$ hrs = 50 hrs

Therefore, Watch is correct 2 days 2 hrs. after 12 p.m on monday i.e it will be correct at 2 p.m on wednesday.

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Q:

A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?

A) 2 p.m. on Tuesday	B) 2 p.m. on Wednesday
C) 3 p.m. on Thursday	D) 1 p.m. on Friday

Answer & Explanation Answer: B) 2 p.m. on Wednesday

Explanation:

Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.

The Watch gains $(2 + 4 \frac{4}{5})$ min. or $\frac{34}{5}$ min.in 170 hrs.

Now, $\frac{34}{5}$ min.are gained in 170 hrs.

2 min.are gained in $(170 * \frac{5}{34} * 2)$ hrs=50 hrs

Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday

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Filed Under: Clock puzzles

Q:

A watch which gains uniformly ,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec.fast at 8 p.m on following sunday. when was it correct?

A) 7pm on wednesday	B) 20 min past 7pm on wednesday
C) 15min past 7pm on wednesday	D) 8pm on wednesday

Answer & Explanation Answer: B) 20 min past 7pm on wednesday

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains $5 + 5 \frac{48}{60}$ min in a time of (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

$\frac{54}{5} m i n \to 180 h o u r s$

5min ->

$(\frac{5}{\frac{54}{2}} \times 180)$

$83 \frac{1}{3} h r s = 72 h r s + 11 \frac{1}{3} h r s = 3 d a y s + 11 h r s + 20 m i n$

So the correct time will be shown on wednesday at 7:20 PM

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

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