9
Q:

A person lends Rs. 300 to A at 4% and Rs.540 to B at 6% for the same time. if the total amount that he gets at the end is Rs. 1032. What is the time? 

Answer:
Q:

A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay : 

A) Rs. 100 B) Rs. 105
C) Rs. 115 D) Rs. 110
 
Answer & Explanation Answer: C) Rs. 115

Explanation:

Amount to be paid =  = Rs. 115.

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8 223
Q:

The simple interest on a sum of money is 1/9 of the principal and the number of years is equal to the rate percent per annum. The rate percent per annum is?

Answer

Let the sum be Rs.x, then S.I = Rs. \inline \frac{x}{9}


Let the rate be R% per annum and the time be  R years then \inline \frac{x}{9}=\frac{x\times R\times R}{100}


\inline \Rightarrow R=\sqrt{\frac{100}{9}}=\frac{10}{3}=3\frac{1}{3} %

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23 1931
Q:

At What rate percent per annum will a sum of money double itself is 12 years?

Answer

Let the principal be Rs. P and the rate be R% per annum


Since  it doubles in 12 years. 


So, simple interest is Rs. P


\inline \therefore \inline P=\frac{P\times R\times 12}{100}


\inline \Rightarrow 12R = 100


\inline \Rightarrow R=\frac{100}{12}=8\frac{1}{3} %


\inline \therefore Hence, rate = \inline 8\frac{1}{3} % per annum

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21 645
Q:

Mohan borrowed a sum of Rs. 12000 at 15% per annum from a money -lender on 13th January 1987 and returned the amount on 8th June 1987 to clear his debt. what was the amount by Mohan to the money-lender to clear his debt?

Answer

Here P= Rs. 12,000 , R= 15%


T = Money kept for the No of days divided by 365


\inline \Rightarrow Jan (31-13) = 18 days


     Feb               = 28 days


     March           = 31 days


     April             = 30 days


     May              = 31 days


     June             = 8 days 


Total = 146 days


\inline \therefore T = \inline \frac{146}{365}=\frac{2}{5} years


\inline \therefore S.I = \inline \frac{P\times R\times T}{100}


         = \inline \frac{12000\times 15\times 2}{100\times 5} years


         = Rs. 720


A = 12000 + 720 = Rs. 12720


Mohan paid Rs. 12,720 to the money-lender to clear his debt.

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3 463
Q:

What annual installment will discharge a debt of Rs. 1092 due in 3 years at 12% S.I?

Answer

Let each installment be Rs. x, then 


 =\inline (x+\frac{x\times 12\times 1}{100})+(x+\frac{x\times 12\times 2}{100})+x=1092


\inline \Rightarrow \inline \frac{28x}{25}+\frac{31x}{25}+x=1092


\inline \Rightarrow x=\frac{1092\times 25}{84}=325


\inline \therefore Each instalment = Rs. 325

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4 421