Here P= Rs. 12,000 , R= 15%

T = Money kept for the No of days divided by 365

Jan (31-13) = 18 days

Feb = 28 days

March = 31 days

April = 30 days

May = 31 days

June = 8 days

Total = 146 days

T = years

S.I =

= years

= Rs. 720

A = 12000 + 720 = Rs. 12720

Mohan paid Rs. 12,720 to the money-lender to clear his debt.

A) Rs. 6000 | B) Rs. 5550 |

C) Rs. 7500 | D) Rs. 6580 |

Explanation:

Let the sum invested be Rs. P

Let the rate of interest be R% per annum

=> Interest earned for 5 years = (P x 5 x R/100) = PR/20

Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%

=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100

Hence,

PR/20 + 10P/100 = PR/20 + 600

=> P = 6000

Therefore, the sum invested is **Rs. 6000**

A) Rs. 101 | B) Rs. 98.5 |

C) Rs. 124.3 | D) Rs. 112.5 |

Explanation:

Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest

She also lends it at 6 1⁄4% p.a for 2 years

=> Total Gain = 6 1/4% − 4% = 2 1/4%

So her gain in the transaction for 1 year

= The simple interest she gets for Rs.5000 for 1 year at 2 1⁄4% per annum

= = Rs. 112.5/ year.

A) 9850 | B) 9500 |

C) 9620 | D) 9760 |

Explanation:

As the interest rate increases by 2%

=> (7000x3x2)/100 = 420

9200

--------

9620

A) JxJ = KL | B) KxK= JL |

C) LxL = JK | D) JKL = 1 |

Explanation:

Let the Time be 'N' and Rate be 'R'

J = (K x NR)/100 K = (L x NR)/100

J/K = NR/100 K/L = NR/100

J/K = K/L

= JL

A) 4.58 % | B) 5.96 % |

C) 6.52 % | D) 4.98 % |

Explanation:

Difference in amount = 514 - 415 = 99

99 = (415 x 4 x R)/100

R = 5.96%