Let the sum be Rs.x, then S.I = Rs.

Let the rate be R% per annum and the time be R years then

%

A) 14.5% | B) 11% |

C) 12% | D) 10.5% |

Explanation:

Let the interest rate be r%

We know that,

S.I = PTR/100

=> (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788

=> r = 178800/14900 = 12%

A) Rs. 6000 | B) Rs. 5550 |

C) Rs. 7500 | D) Rs. 6580 |

Explanation:

Let the sum invested be Rs. P

Let the rate of interest be R% per annum

=> Interest earned for 5 years = (P x 5 x R/100) = PR/20

Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%

=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100

Hence,

PR/20 + 10P/100 = PR/20 + 600

=> P = 6000

Therefore, the sum invested is **Rs. 6000**

A) Rs. 101 | B) Rs. 98.5 |

C) Rs. 124.3 | D) Rs. 112.5 |

Explanation:

Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest

She also lends it at 6 1⁄4% p.a for 2 years

=> Total Gain = 6 1/4% − 4% = 2 1/4%

So her gain in the transaction for 1 year

= The simple interest she gets for Rs.5000 for 1 year at 2 1⁄4% per annum

= = Rs. 112.5/ year.

A) 9850 | B) 9500 |

C) 9620 | D) 9760 |

Explanation:

As the interest rate increases by 2%

=> (7000x3x2)/100 = 420

9200

--------

9620

A) JxJ = KL | B) KxK= JL |

C) LxL = JK | D) JKL = 1 |

Explanation:

Let the Time be 'N' and Rate be 'R'

J = (K x NR)/100 K = (L x NR)/100

J/K = NR/100 K/L = NR/100

J/K = K/L

= JL