2
Q:

Simplyfiy : $\left[3\frac{1}{4}÷\left\{1\frac{1}{4}-\frac{1}{2}\left(2\frac{1}{2}-\left(\overline{)\frac{1}{4}+\frac{1}{6}}\right)\right)\right\}\right]$

 A) 78 B) 88 C) 98 D) 108

Explanation:

Given exp =$\left[\frac{13}{4}÷\left\{\frac{5}{4}-\frac{1}{2}\left(\frac{5}{2}-\frac{3-2}{12}\right)\right\}\right]$$\left[\frac{13}{4}÷\left\{\frac{5}{4}-\frac{1}{2}\left(\frac{5}{2}-\frac{1}{12}\right)\right\}\right]$

$\left[\frac{13}{4}÷\left\{\frac{5}{4}-\frac{1}{2}\left(\frac{30-1}{12}\right)\right\}\right]$ = $\left[\frac{13}{4}÷\left\{\frac{5}{4}-\frac{29}{24}\right\}\right]$

= $\left[\frac{13}{4}÷\frac{30-29}{24}\right]$=78

Q:

 A) 68947 B) 69874 C) 70000 D) 76000

Explanation:

= 70,000.

8 179
Q:

Simplify $\left(2\sqrt{392}-21\right)+{\left(\sqrt{8}-7\right)}^{2}={\left(\mathbf{?}\right)}^{\mathbf{2}}$

 A) 4 B) 5 C) 6 D) 9

Explanation:

5 112
Q:

Find the value of '?'

 A) 166251 B) 166259 C) 166252 D) 166253

Explanation:

Given

Using unit digit method,

On LHS,

1 x 1 x 1 = 1

sqrt of last digit 1 => it must end with either 9 or 1

so now

1 x 1 = 1

1 x 9 = 9

On RHS,

? + 89

=> ? = ...1 - 89 = last digit is 11- 9 = 2

or

=> ? = ...9 - 89 = last digit is 9 - 9 = 0

Here in the options last digit 2 is option C.

10 158
Q:

1397 x 1397 = ?

Here what replaces '?'

 A) 1951609 B) 1821504 C) 2031489 D) 1847879

Explanation:

1397 x 1397

5 225
Q:

Given that 100.48 = x,  100.70 = y and xz = y2,  then the value of z is close to ___ ?

 A) 3.7 B) 2.7 C) 3.6 D) 2.9

Explanation:

xz = y2        10(0.48z) = 10(2 x 0.70) = 101.40

0.48z = 1.40

z = 140/18 = 35/12 = 2.9 (approx.)

7 204
Q:

The price of 2 oranges, 3 bananas and 4 apples is Rs. 15. The price of 3 oranges, 2 bananas and 1 apple is Rs. 10. What will be price of 4 oranges, 4 bananas and 4 apples  ?

 A) Rs. 10 B) Rs. 15 C) Rs. 20 D) Rs. 25

Explanation:

Let the Oranges be 'O', Bananas be 'B' and Apples be 'A'

From the given data,

2O + 3B + 4A = 15 ...... (I)

3O + 2B + A = 10 ..... (II)

5O + 5B + 5A = 25

O + B + A = 5

4O + 4B + 4A = 20.

8 735
Q:

Simplify the following :

$\frac{{37}^{3}+{35}^{3}+{28}^{3}-3x37x35x28}{{37}^{2}+{35}^{2}+{28}^{2}-37x35-35x28-37x28}$ ?

 A) 100 B) 1 C) 4 D) 0

Explanation:

Given $\frac{{37}^{3}+{35}^{3}+{28}^{3}-3x37x35x28}{{37}^{2}+{35}^{2}+{28}^{2}-37x35-35x28-37x28}$

It is in the form of

$\frac{{\mathbf{a}}^{\mathbf{3}}\mathbf{+}{\mathbf{b}}^{\mathbf{3}}\mathbf{+}{\mathbf{c}}^{\mathbf{3}}\mathbf{-}\mathbf{3}\mathbf{a}\mathbf{b}\mathbf{c}}{{\mathbf{a}}^{\mathbf{2}}\mathbf{+}{\mathbf{b}}^{\mathbf{2}}\mathbf{+}{\mathbf{c}}^{\mathbf{2}}\mathbf{-}\mathbf{a}\mathbf{b}\mathbf{-}\mathbf{b}\mathbf{c}\mathbf{-}\mathbf{c}\mathbf{a}}$= a + b + c

Here a = 37, b = 35 & c = 28

=> a + b + c = 37 + 35 + 28 = 100

Therefore, $\inline \fn_jvn \frac{(37)^{3}+(35)^{3}+(28)^{3}-3x37x35x28}{(37)^{2}+(35)^{2}+(28)^{2}-37x35-35x28-37x28}$  = 100

6 500
Q:

In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ?

 A) 63 B) 62 C) 64 D) 65