A) 2000 | B) 3000 |

C) 2500 | D) 3500 |

Explanation:

Let 's' be the number of small packets and 'b' the number of large packets sold on that day.

Therefore, s + b = 5000 ... eqn (1)

Each small packet was sold for Rs.150.

Therefore, 's' small packets would have fetched Rs.150s.

Each large packets was sold for Rs.250.

Therefore, 'b' large packets would have fetched Rs.250b.

Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)

Or 150s + 250b = 10,50,000 ... eqn (2)

Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)

Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000

Or b = 3000

We know that s + b = 5000

So, s = 5000 - b = 5000 - 3000 = 2000.

2000 small packets were sold.

A) K = b /a | B) bL = -a |

C) KL = 1 | D) aK = -b |

A) 15 | B) 20 |

C) 10 | D) 8 |

Explanation:

Let the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy

=>5(300/x) - 10x - 50 = 0 =>

multiplying both sides by -1/10x

=>

=> x(x + 15) - 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.

A) 300 | B) 150 |

C) 175 | D) 200 |

Explanation:

Half of the cloth = 37.5/2

From 1 meter he will make 8 pieces

=> in 37.5/2 ---- ?

37.5/2 x 8

= 150.

A) A | B) C |

C) Both A and B | D) All are equal |