A) 456 kms | B) 482 kms |

C) 552 kms | D) 556 kms |

Explanation:

Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms)

This is an A.P with first term, a=35, number of terms,

n= 12,d=2.

Required distance = 12/2[2 x 35+{12-1) x 2]

=6(70+23)

= 552 kms.

A) 1.5 hrs | B) 1.7 hrs |

C) 2.2 hrs | D) 3.5 hrs |

Explanation:

Let the original Speed be "s" kmph

And the usual time be "t" hrs

Given that if the bus is running at 9s/10 kmph the time is 22 hrs

=> 9s/10 x 22 = t x s

=> 99/5 = t

=> t = 19.8 hrs

Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.

A) 48 | B) 52 |

C) 38 | D) 42 |

Explanation:

Here distance d = 800 mts

speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s

time t = 800x18/(60x5) = 48 sec.

A) 3 km/hr | B) 4 km/hr |

C) 5 km/hr | D) 6 km/hr |

Explanation:

Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.

So, 24/x + 24/(7 - x) = 14

- 98x + 168 = 0

(x - 3)(x - 4) = 0 => x = 3 or 4.

Since, P is faster than Q,

so P's speed = 4 km/hr and Q's speed = 3 km/hr.

A) 12.4 hrs | B) 11.9 hrs |

C) 10.7 hrs | D) 9.9 hrs |

Explanation:

We know that

Time = Distance/speed

Required time = (10 1/4)/2 + (10 1/4)/6

= 41/8 + 41/6

= 287/24 = 11.9 hours.

A) 6 hrs 24 min | B) 6 hrs |

C) 7 hrs 21 min | D) 6 hrs 28 min |

Explanation:

Time taken to cover 600 km = 600/100 = 6 hrs.

Number of stoppages = 600/75 - 1 = 7

Total time of stoppages = 4 x 7 = 28 min

Hence, total time taken = 6 hrs 28 min.