A) 12 a.m. | B) 1 p.m. |

C) 11 a.m. | D) 12 p.m. |

Explanation:

Assume both trains meet after 'p' hours after 7 a.m.

Distance covered by train starting from A in 'p' hours = 20p km

Distance covered by train starting from B in (p-1) hours = 25(p-1)

Total distance = 200

=> 20x + 25(x-1) = 200

=> 45x = 225

=> p= 5

Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

A) 5.75 kms | B) 7.36 kms |

C) 8.2 kms | D) 6.98 kms |

Explanation:

Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

A) 6:00 am | B) 6:30 pm |

C) 5:45 am | D) 5:52 pm |

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

A) 99 | B) 100 |

C) 89 | D) 1 |

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

=>

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

A) 54 kms | B) 32 kms |

C) 45 kms | D) 60 kms |

Explanation:

Let the distance be d.

=> 2d = 120

=> d = 60 kms.

A) 36 sec | B) 39 sec |

C) 41 sec | D) 43 sec |

Explanation:

Speed = 44 kmph x 5/18 = 110/9 m/s

We know that, Time = distance/speed

Time = (360 + 140) / (110/9)

= 500 x 9/110 = 41 sec.