A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = = 6

Number of pages typed by Smith in 1 hour = = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = 8 = 8 hrs 34 min.

A) 10 days | B) 14 days |

C) 11 days | D) 9 days |

Explanation:

30 x 25 = 750

425

-----------

325

25 + 7.50 = 32.5

=> 325/32.5 = 10

A) 40 days | B) 36 days |

C) 32 days | D) 34 days |

Explanation:

Let 1 man's 1 day work = x and 1 woman's 1 day work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10

Solving these two equations, we get:

x = 11/400 and y = 1/400

10 woman's 1 day work = (1/400 x 10) = 1/40.

Hence, 10 women will complete the work in 40 days.

A) 7 | B) 8 |

C) 9 | D) 10 |

Explanation:

As the work is same

M1D1 = M2D2

Here Let the number of men employed was M

=> 11M = 7(M+4)

=> 11M - 7M = 28

=> M = 7

A) 18 days | B) 20 days |

C) 16 days | D) 14 days |

Explanation:

(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 x 8)/4 = 20 days.

A) 1:2 | B) 1:3 |

C) 3:1 | D) 2:1 |

Explanation:

5M + 2B = 4(1M + 1B)

5M + 2B = 4M + 4B

1M = 2B

The required ratio of work done by a man and a boy = 2:1