A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = = 6

Number of pages typed by Smith in 1 hour = = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = 8 = 8 hrs 34 min.

A) 3 am | B) 12 pm |

C) 1 pm | D) 3 pm |

Explanation:

Work done by P and Q in the first two hours, working alternately

= First hour P + Second hour Q

work is completed in 2 hours

Then, the total time required to complete the work by P and Q working alternately=23=6hours

Thus, work will be completed at 3pm.

A) 30 days | B) 40 days |

C) 120 days | D) 80 days |

Explanation:

Given K=4L

K+L = 4L+L = 5L

These 5L people can complete the work in 24 days, which means L alone can do the work in

245=120 days.

Hence, K alone can do the work in = 30 days.

A) 11 days | B) 12 days |

C) 13 days | D) 14 days |

Explanation:

One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

A) 4 days | B) 5 days |

C) 6 days | D) 7 days |

Explanation:

Work donee by A and B in the first two hours, working alternatively = First hour A + Second hour B = (1/4) + (1/12) = 1/3.

Thus, the total time required to complete the work = 2 (3) = 6 days

A) 2 hours | B) 8 hours |

C) 6 hours | D) 4 hours |

Explanation:

Efficiency of Inlet pipe A = 4.16%

Efficiency of Inlet pipe B = 5.83%

Efficiency of A and B together = 100 %

Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x)

Now, since this amount of water is being emptied by C at x% per hour, then

x = 8%

Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours