A) 8 hrs 45 min | B) 8 hrs 42 min |

C) 8 hrs | D) 8 hrs 34 min |

Explanation:

Number of pages typed by Adam in 1 hour = 36/6 = 6

Number of pages typed by Smith in 1 hour = 40/5 = 8

Number of pages typed by both in 1 hour = (6 + 8) = 14

Time taken by both to type 110 pages = (120 * 1/14) = $8\frac{4}{7}$ = 8 hrs 34 min.

A) 5 (2/3) | B) 6 (3/4 ) |

C) 4 (1/2) | D) 3 |

Explanation:

Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9

They would take 9/2 days = 4 (1/2) days to complete the work working together.

A) 14 1/2 days | B) 11 days |

C) 13 1/4 days | D) 12 6/7 days |

Explanation:

Let 'B' alone can do the work in 'x' days

6/30 + 18/x = 1

=> x = 22.5

1/30 + 1/22.5 = 7/90

=> 90/7 = 12 6/7 days

A) 1/6 | B) 1/3 |

C) 2/3 | D) 1/18 |

Explanation:

K's one day's work = 1/30

L's one day's work = 1/45

(K + L)'s one day's work = 1/30 + 1/45 = 1/18

The part of the work completed in 3 days = 3 (1/18) = 1/6.

A) 1/7 min | B) 7/2 min |

C) 5/7 min | D) 7/5 min |

Explanation:

Time taken to fill 2/7 = 1

Then to fill full 1 = ?

? = 1/(2/7) = 7/2 minutes.

A) 101 men | B) 112 men |

C) 102 men | D) 120 men |

Explanation:

From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2)

so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)]

so, M = 136 men

Number of men to be added to finish the work = 136-34 = 102 men.

A) 36 | B) 61 |

C) 48 | D) 54 |

A) 10 2/3 days | B) 13 1/5 days |

C) 12 2/3 days | D) 11 5/7 days |

Explanation:

3/15 + 4/16 + x/24 = 1

$\Rightarrow x=13\frac{1}{5}$

A) 8 hrs | B) 12 hrs |

C) 6 hrs | D) 4 hrs |

Explanation:

Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.

Then, (1/x + 2/x + 3/x) = 1/2

=> 6/x = 1/2 => x = 12

So, B takes 6 hours to finish the work.