A) 6 | B) 8 |

C) 9 | D) 12 |

Explanation:

Amit did the work in 56 days =

Rest work was done by Amit and Bharath = = 8 days

( since Amit and Bharath do the work in one day = )

A) 44 | B) 32 |

C) 56 | D) 49 |

Explanation:

Girl eats 112 chocolates in 30 sec

so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates.

Her boy friend can eat one-half of 112 in twice of 30 sec

so he can eat 56 in 60 sec

Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates.

Hence, together they can eat

=> 44.8 + 11.2

56 chocolates in 12 seconds.

A) 24 $ | B) 22 $ |

C) 16 $ | D) 14 $ |

Explanation:

Let the 1 day work of a boy=b and a girl=g, then

2b + g = 1/5 ---(i) and

b + 2g = 1/6 ---(ii)

On solving (i) & (ii), b=7/90, g=2/45

As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,

so a girl will be paid 28x = 16 $.

A) 3 days | B) 26/3 days |

C) 13/4 days | D) 24/5 days |

Explanation:

we know that **m1 x d1 = m2 x d2**

=> 4 x 6 = 5 x d

where d = no. of days taken by 5 men to paint

d = 24/5 days.

A) 2 days | B) 3 days |

C) 4 days | D) 5 days |

Explanation:

One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I)

One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II)

Divide both sides by 2 in (I) and then multiply both sides by 5

Now we get

15b + 20g = 1/4.

Therefore, 15 boys and 20 girls can do the same work in 4 days.

A) 145 | B) 165 |

C) 175 | D) 135 |

Explanation:

Given that

working days = 5;

working hours = 8;

A man get rupess per hour is Rs.2.40;

So in one day the man get total rupees is 2.40 x 8 = 19.2

So in 5 days week the man get total rupees is 19.2 x 5 = 96

So in 4 week the man get total rupees is 96 x 4 = 384

So the man worked for = 160hours in 4 weeks

But given that the man earned Rs.432

Hence remaning money is (432-384 = 48)which is earn by doing overtime work

Overtime hours is = 48/3.20 = 15

So total worked hours is = 15 + 160 = 175.