A) 2 hours | B) 8 hours |

C) 6 hours | D) 4 hours |

Explanation:

Efficiency of Inlet pipe A = 4.16%

Efficiency of Inlet pipe B = 5.83%

Efficiency of A and B together = 100 %

Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x)

Now, since this amount of water is being emptied by C at x% per hour, then

x = 8%

Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours

A) 4 days | B) 8 days |

C) 3 days | D) 6 days |

Explanation:

4/10 + 9/x = 1

=> x = 15

Then both can do in

1/10 + 1/15 = 1/6

=> 6 days

A) 2 days | B) 2.5 days |

C) 2.25 days | D) 3 days |

Explanation:

1 man's 1 day work = 1/108

12 men's 6 day's work = 1/9 x 6 = 2/3

Remaining work = 1 - 2/3 = 1/3

16 men's 1 day work = 1/108 x 16 = 4/27

4/27 work is done by them in 1 day.

1/3 work is done by them in 27/4 x 1/3 = 9/4 days.

A) 5 (2/3) | B) 6 (3/4 ) |

C) 4 (1/2) | D) 3 |

Explanation:

Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.

A) 14 1/2 days | B) 11 days |

C) 13 1/4 days | D) 12 6/7 days |

Explanation:

Let 'B' alone can do the work in 'x' days

6/30 + 18/x = 1

x = 22.5

1/30 + 1/22.5 = 7/90

=> 90/7 = 12 6/7 days

A) 1/6 | B) 1/3 |

C) 2/3 | D) 1/18 |

Explanation:

K's one day's work = 1/30

L's one day's work = 1/45

(K + L)'s one day's work = 1/30 + 1/45 = 1/18

The part of the work completed in 3 days = 3 (1/18) = 1/6.