A) 360, 160, 200 | B) 160, 360, 200 |

C) 200, 360,160 | D) 200,160,300 |

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

A) X | B) W |

C) I | D) H |

Explanation:

In the given alphabet, last but one letter of alphabet is Y.

10th letter to the left of Y is O

8th letter to the right of O is W

A) Earthquakes | B) Rainfall |

C) Ocean depth | D) Sound intensity |

Explanation:

**Fathometer** is used to measure **Ocean depth.**

Fathometer is A** depth finder** that uses sound waves to determine the depth of water.

The Richter Scale* *is used to measure the intensity of Earthquakes.

The Decibel Scale is used to measure sound intensity.

A) MFEDJJOE | B) EOJDEJFM |

C) MFEJDJOE | D) EOJDJEFM |

Explanation:

- There are 8 letters in the word.

- The coded word can be obtained by taking the immediately following letters of word, expect the first and the last letters of the given word but in the reverse order. That means, in the coded form the first and the last letters have been interchanged while the remaining letters are coded by taking their immediate next letters in the reverse order.

A) None | B) One |

C) Two | D) Three |

Explanation:

**Given Number:** 4 2 1 5 7 9 3 6 8

**Ascending order: **1 2 3 4 5 6 7 8 9

Hence the required pairs are 12, 49, 16

A) 3 | B) 4 |

C) 5 | D) 6 |

Explanation:

Looking into the alphabets there are six such pairs namely ON, HONE, ST, TRAPHO, TRAPHON, RAP.

1. ON - NO

2. HONE - EFGH

3. ST - ST

4. TRAPHO - OPQRST

5. TRAPHON - NOPQRST

6. RAP - PQR

A) North-East | B) North-West |

C) South-East | D) South-West |

Explanation:

It is clear from the diagrams that new name of West will become South-East.

A) 20 | B) 30 |

C) 40 | D) 50 |

Explanation:

The fruit content in both the fresh fruit and dry fruit is the same.

Given, fresh fruit has 68% water.so remaining 32% is fruit content. weight of fresh fruits is 100kg

Dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.

Fruit % in freshfruit = Fruit% in dryfruit

Therefore, (32/100) x 100 = (80/100 ) x y

we get, y = 40 kg.