0
Q:

Kramer borrowed $4000 from George at an interest rate of 7% compounded semiannually. The loan is to be repaid by three payments. The first payment, $1000, is due two years after the date of the loan. The second and third payments are due three and five years, respectively, after the initial loan. Calculate the amounts of the second and third payments if the second payment is to be twice the size of the third payment.

A) 1389 B) 1359
C) 1379 D) 1339.33

Answer:   D) 1339.33



Explanation:

Given:j=7% compounded semiannually making m=2 and i = j/m= 7%/2 = 3.5%
Let x represent the third payment. Then the second payment must be 2x.
PV1,PV2, andPV3 represent the present values of the first, second, and third payments.

Since the sum of the present values of all payments equals the original loan, then
PV1 + PV2  +PV3  =$4000 -------(1)

PV1   =FV/(1 + i)^n  =$1000/(1.035)^4=  $871.44

At first, we may be stumped as to how to proceed for
PV2 and PV3. Let’s think about the third payment of x dollars. We can compute the present value of just $1 from the x dollars

pv=1/(1.035)^10=0.7089188

PV2   =2x * 0.7089188 = 1.6270013x
PV3   =x * 0.7089188=0.7089188x
Now substitute these values into equation ➀ and solve for x.
$871.442 + 1.6270013x + 0.7089188x  =$4000

2.3359201x  =$3128.558

x=$1339.326
Kramer’s second payment will be 2($1339.326)  =$2678.65, and the third payment will be $1339.33

Subject: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO
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Answer & Explanation Answer: D) Rs.3200

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A) 21750 B) 22050
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A sum of Rs 4000 becomes Rs 5800 in 3 years, when invested in a scheme of simple interest. If the same sum is invested in a scheme of compound interest with same yearly interest rate (compounding of interest is done yearly), then what will be the amount (in Rs) after 2 years?

 

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The maturity value of a certain sum after two years at 20% p.a. interest compounded annually is Rs. 14,400/-. Find the Principal amount.

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Shams invested Rs. 5000 at 10% per annum compound interest. After n years, Shams received Rs. 1655 more. Find the value of n.

 

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