Bank Clerk Questions


Q:

The number of signals that can be generated by using 5 differently coloured flags, when any number of them may be hoisted at a time is:

A) 235 B) 253
C) 325 D) None of these
 
Answer & Explanation Answer: C) 325

Explanation:

Required number of signals = 5P1 + 5P2 + 5P3 + 5P4 + 5P5

= 5 + 20 + 60 + 120 + 120 = 325

 

 

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Filed Under: Permutations and Combinations
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4 5342
Q:

In how many ways can 100 soldiers be divided into 4 squads of 10, 20, 30, 40 respectively?

A) 1700 B) 18!
C) 190 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

100C10 + 90C20 + 70C30 + 40C40 = 100!10!x20!x30!x40!

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2 8854
Q:

What is the total no of ways of selecting atleast one item from each of the two sets containing 6 different items each?

A) 2856 B) 3969
C) 480 D) None of these
 
Answer & Explanation Answer: B) 3969

Explanation:

We can select atleast one item from 6 different items = 26-1  

 

Similarly we can select atleast one item from other set of 6 different items in 26-1 ways. 

 

Required number of ways = (26-1)26-1 = 26-12 = 3969

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1 6412
Q:

If a+b+c =21 what is the total number of positive integral solutions?

A) 109 B) 190
C) 901 D) 910
 
Answer & Explanation Answer: B) 190

Explanation:

Number of positive integral solutions =  n-1Cr-1 = C220 = 190

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6 8526
Q:

If a+b+c = 21, what is the total number of non - negative integral solutions?

A) 123 B) 253
C) 321 D) 231
 
Answer & Explanation Answer: B) 253

Explanation:

Number of non - negative integral solutions =n+r-1 Cr-1 = C223 = 253 

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4 6836
Q:

How many different words can be made using the letters of the word ' HALLUCINATION ' if all constants are together?

A) 129780 B) 1587600
C) 35600 D) None of these
 
Answer & Explanation Answer: B) 1587600

Explanation:

 H   L   C   N    T    A   U   I   O

 

      L        N          A        I

 

There are total 131 letters out of which 7 are consonants and 6 are vowels. Also ther are 2L's , 2N's, 2A's and 2I's.

 

If all the consonants  are together then the numberof arrangements = 7!2!x 1/2! .

But the 7 consonants  can be arranged themselves in  7!2! x 1/2! ways. 

 

Hence the required number of ways = 7!2!2!2 = 1587600

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7 14882
Q:

A Group consists of 4 couples in which each of the  4 persons have one wife each. In how many ways could they be arranged in a straight line such that the men and women occupy alternate positions?

A) 1152 B) 1278
C) 1296 D) None of these
 
Answer & Explanation Answer: A) 1152

Explanation:

Case I :  MW  MW  MW  MW

 

Case II:  WM  WM  WM  WM

 

Let us arrange 4 men in 4! ways, then we arrange 4 women in 4P4 ways at 4 places either left of the men or right of the men. Hence required number of arrangements

 

   4! × 4P4  + 4! × 4P4  = 2 × 576 = 1152

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4 9951
Q:

The least value of the expression 2log10x - logx1100 for x>1 is:

A) 2 B) 3
C) 4 D) 5
 
Answer & Explanation Answer: C) 4

Explanation:

 

Hence the least value of is 4

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44 6474