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Bank PO Questions

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Q:

A sector of 120 degrees, cut out from a circle, has an area of 66/7 sq cm. Find the radius of the circle.

A) 1cm B) 2cm
C) 3cm D) 4cm
 
Answer & Explanation Answer: C) 3cm

Explanation:

πr=667

 r =3

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Q:

The inner circumference of a circular race track, 14m wide is 440m. Find the radius of the outer circle.

A) 84m B) 24m
C) 44m D) 54m
 
Answer & Explanation Answer: A) 84m

Explanation:

let inner radius be r meters. 

2πr=440⇒r=440×744=70mradius of outer circle =70+14m  

 

Therefore, Radius of outer circle = 70 + 14 = 84m

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Q:

Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 9856 sq meters.

A) 56m B) 16m
C) 14m D) 76m
 
Answer & Explanation Answer: A) 56m

Explanation:

clearly the cow will graze a circular field of area 9856 sq m and radius equal to the length of the rope.


Let the length of the rope be r mts 

then, πr2=9856 ⇒ r2=9856×722=3136 ⇒r =56m

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Q:

The base of a triangle of 15cm and height is 12cm. The height of another triangle of double the area having the base 20cm is

A) 16 B) 17
C) 18 D) 20
 
Answer & Explanation Answer: C) 18

Explanation:

a = 12×15×12 = 90 sq.cm  

b = 2a = 12×20×h  

h= 18cm

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Q:

The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is

A) Rs.174 B) Rs.274
C) Rs.374 D) Rs.474
 
Answer & Explanation Answer: D) Rs.474

Explanation:

Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m

Cost of painting = Rs. 158 x 3 = Rs. 474

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Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

A) Rs. 258 B) Rs. 358
C) Rs. 458 D) Rs. 558
 
Answer & Explanation Answer: D) Rs. 558

Explanation:

Area to be plastered = 2l+b×h+l×b 

=225+12×6+25×12=744sq.m 

Cost of plastering = 744×75100=Rs.558                       

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Q:

An error of 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is

A) 4.04% B) 5.04%
C) 6.04% D) 7.04%
 
Answer & Explanation Answer: A) 4.04%

Explanation:

100 cm is read as 102 cm

 

a = 100 x 100 sq.cm and b = 102 x 102 sq.cm

 

then, Increase in area = [ (102 x 102) - (100 x 100) ] sq.cm

 

percentage error =404100*100*100= 4.04%

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Q:

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

A) a B) a>b
C) a=b D) none
 
Answer & Explanation Answer: B) a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm

then perimeter of square = perimeter of rectangle

area of square = 16 sq.cm

area of rectangle = 12 sq.cm

Hence a >b

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