Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

'Extensively' is describing the verb 'flew' and should be placed after the verb and thus the correct phrase should be 'extensively over'. The error is in the second part of the sentence.

As per the provisions of Section 12 of the Banking Regulation Act, 1949, the minimum ratio should be 4:2:1.

12 year old Padmalaya Nanda from Odisha has created history by becoming the youngest girl to bag the two "Little Miss Universe Internet 2017" and "Little Miss Actress" crowns at the 'Little Miss Universe-2017' at port city of Batumi in Georgia. Padmalaya Nanda, who studies in the 8th standard at a school in Cuttack, Odisha, bagged the crowns at the finale of the little Universe 2017, held at port city of Batumi in Georgia on June 4, 2017.

The two events mentioned are independent.

The first roll of the die is independent of the second roll. Therefore the probabilities can be directly multiplied.

P(getting first 4) = 1/6

P(no second 6) = 5/6

Therefore P(getting first 4 and no second 6) = 1/6 x 5/6 = 5/36

These two events cannot be disjoint because P(K) + P(L) > 1.

P(AꓴB) = P(A) + P(B) - P(AꓵB).

An event is disjoint if P(A ꓵ B) = 0. If K and L are disjoint P(K ꓴ L) = 0.8 + 0.6 = 1.4

And Since probability cannot be greater than 1, these two mentioned events cannot be disjoint.

Eminent poet, litterateur and Jnanpith awardee C. Narayana Reddy, popularly known as CiNaRe, passed away.  CiNaRe was known for his use of Telugu in its pure form, and would not be swayed by filmmakers on the use of the language. He was awarded the Padma Shri in 1977 and the Padma Bhushan in 1992. His compilation of poems, titled ‘Viswambhara’, got him the Jnanpith award in 1988. In 1997, he was nominated as a Member of the Rajya Sabha.

Relative speed = 60 + 90 = 150 km/hr.

= 150 x 5/18 = 125/3 m/sec.

Distance covered = 1.10 + 0.9 = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec.