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Q:

If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?

A) Rs. (xy/d)	B) Rs. (xd)
C) Rs. (yd)	D) Rs. (yd/x)

Answer & Explanation Answer: D) Rs. (yd/x)

Explanation:

Cost of x metres = Rs. d.

Cost of 1 metre = Rs.(d/x)

Cost of y metres = Rs.[(d/x).y] = Rs.(yd/x)

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Filed Under: Chain Rule

Q:

If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?

A) 48 paise	B) 54 paise
C) 56 paise	D) 72 paise

Answer & Explanation Answer: A) 48 paise

Explanation:

Let the required weight be x kg.

Less weight, Less cost (Direct Proportion)

250 : 200 :: 60 : x => 250 x x = (200 x 60)

=>

=> x = 48.

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Filed Under: Quantitative Aptitude - Arithmetic Ability

Q:

4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

A) 4	B) 8
C) 12	D) 16

Answer & Explanation Answer: D) 16

Explanation:

Let the required number of bottles be x.

More weavers, More mats (Direct Proportion)

More days, More mats (Direct Proportion)

$W a v e r s 4 : 8 D a y s 4 : 8$ :: 4:x

4 x 4 x x = 8 x 8 x 4

=> x= $\frac{8 * 8 * 4}{4 * 4}$

=> x = 16.

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Filed Under: Quantitative Aptitude - Arithmetic Ability

Q:

If the price of 23 toys is 276, then what will the price of 12 toys ?

A) 144	B) 148
C) 156	D) 186

Answer & Explanation Answer: A) 144

Explanation:

Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,

23:12::276:x => x=(276*12)/23

=> x=144

So price of 12 toys will be Rs. 144

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Filed Under: Chain Rule

Q:

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?

A) Data inadequate	B) 8 units
C) 12 units	D) None of these

Answer & Explanation Answer: A) Data inadequate

Explanation:

One of AB, AD and CD must have given.

So, the data is inadequate.

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Filed Under: Height and Distance

Q:

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A) 173 m	B) 200 m
C) 273 m	D) 300 m

Answer & Explanation Answer: C) 273 m

Explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100m, $∠ A C B = 30 ° a n d ∠ A D B = 45 °$

$\frac{A B}{A C} = \tan 30 ° = \frac{1}{\sqrt{3}} = > A C = A B * \sqrt{3} = 100 \sqrt{3 m}$

$\frac{A B}{A D} = \tan 45 ° = 1 = > A D = A B = 100 m$

CD=(AC+AD)= $(100 \sqrt{3} + 100) m = 100 (\sqrt{3} + 1) = 100 * 2.73 = 273 m$

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Filed Under: Height and Distance

Q:

A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is:

A) 57	B) 67
C) 77	D) 87

Answer & Explanation Answer: C) 77

Explanation:

Money collected = (59.29 x 100) paise = 5929 paise.

Number of members = $\sqrt{5929}$ = 77.

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Filed Under: Square Roots and Cube Roots

Q:

The cube root of .000216 is:

A) .6	B) .06
C) 77	D) 87

Answer & Explanation Answer: B) .06

Explanation:

${(. 000216)}^{\frac{1}{3}} = {(\frac{216}{10^{6}})}^{\frac{1}{3}} = {[\frac{6 * 6 * 6}{10^{2} * 10^{2} * 10^{2}}]}^{\frac{1}{3}} = [\frac{6}{10^{2}}] = 0.06$

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Filed Under: Square Roots and Cube Roots

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